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juin [17]
2 years ago
14

- Calculate the molarity of 23 grams of OH in 24 of water

Chemistry
1 answer:
Vlad [161]2 years ago
3 0

Answer:

mustard gas

Explanation:

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What is the mass of ca(oh)2 in 110. mL of 1.244 M ca(oh)2 solution
stealth61 [152]
<em>V= 110mL = 110cm³ = 0,11dm³</em>
<em>C = 1,244 mol/L = 1,244 mol/dm³</em>


C = n/V
n = 1,244×0,11
<u>n = 0,13684 moles</u>

<em>mCa(OH)₂ = 74 g/mol</em>


1 mole Ca(OH)₂ ------------ 74g
0,13684 ---------------------- X
X = 74×0,13684
<u>X = 10,12616g</u>

:)
7 0
3 years ago
Which element forms the skeleton of this polymer?
WINSTONCH [101]

Answer:

Carbon?

Explanation:

4 0
2 years ago
Biphenyl, c12h10, is a nonvolatile, nonionizing solute that is soluble in benzene, c6h6. at 25 °c, the vapor pressure of pure be
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5 0
3 years ago
Elements occur in a number of isotopic forms. In this problem, you will learn about the notation used to distinguish different i
alina1380 [7]

Answer:

  • <em>Number of protons, Z = 14</em>
  • <em>Number of neutrons, N = 14</em>

Explanation:

<u>1) About isotopes:</u>

<em>Isotopes</em> are different kind of atoms of the same element. Hence, they have the atomic number (Z), which is the number of <em>protons</em>, the same number of electrons (talking about to neutral atoms, not ions), and different <em>number of neutrons N).</em>

This is, it is the number of neutrons what distinguish different isotopes of an element.

<u>2) About the notation used to distinguish different isotopes:</u>

A superscript and a subscript, both to the left of the chemical symbol of the element, are used to <em>distinguish different isotopes</em>:

       A ←------------- This superscript tells the mass number of the isotope

           X ←--------- This is the chemical symbol of the element

      Z ←-------------- This subscript is the atomic number of isotope

In our case, the notiation for the isotope of silicon is:  ²⁸₁₄ Si

So, we have:

  • 28 is the mass number (A)
  • 14 is the atomic number (Z)
  • Si is the chemical symbol.

Now, you can answer the questions of the <em>part A</em>:

  • Number of protons: Z = 14
  • Number of neutrons N:

       mass number = number of protons + number of neutrons

                   A         =                 Z              +                N

⇒ N = A - Z = 28 - 14 = 14

In <u>conclusion</u>:

  • Number of protons, Z = 14
  • Number of neutrons, N = 14
5 0
3 years ago
A 25.0 L tank of nitrogen gas is at 25 oC and 2.05 atm . If the temperature stays at 25 oC and the volume is decreased to 14.5 L
NeTakaya

Answer:

\boxed {\boxed {\sf P_2 \approx 3.53 \ atm}}

Explanation:

In this problem, the temperature stays constant. The volume and pressure change, so we use Boyle's Law. This states that the pressure of a gas is inversely proportional to the volume. The formula is:

P_1V_1=P_2V_2

Now we can substitute any known values into the formula.

Originally, the gas has a volume of 25.0 liters and a pressure of 2.05 atmospheres.

25.0 \ L * 2.05 \ atm = P_2V_2

The volume is decreased to 14.5 liters, but the pressure is unknown.

25.0 \ L * 2.05 \ atm = P_2 * 14.5 \ L

Since we are solving for the new pressure, or P₂, we must isolate the variable. It is being multiplied by 14.5 liters and the inverse of multiplication is division. Divide both sides by 14.5 L .

\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}=\frac{P_2 *14.5 \ L}{14.5 \ L}

\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}= P_2

The units of liters cancel.

\frac {25.0  * 2.05 \ atm }{14.5 }=P_2

\frac {50.25\  atm }{14.5 }=P_2

3.53448276 \ atm = P_2

The original values of volume and pressure have 3 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

  • 3.53448276

The 4 in the thousandth place (in bold above) tells us to leave the 3 in the hundredth place.

3.53 \ atm \approx P_2

The new pressure is approximately <u>3.53 atmospheres.</u>

8 0
2 years ago
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