All categories

4 years ago

A physical structure or a behavior that helps an organism to survive in its environment is

Chemistry

1 answer:

Leto [7]4 years ago

4 0

Answer:

Behavior : adaptation

Explanation:

Animals adapt to environments e.g. Finding new sources of food and housing allows it to survive if environmental changes occur.

You might be interested in

PLEASE HELP! The cooling curve below represents the cooling of a sample of gas. According to the cooling curve, what phase(s) wo

kiruha [24]

According to the cooling curve given above, at temperature 275K, the phases that will be observed is LIQUID AND SOLID.
The flat points on the graph represent the points where phase changes are taking place.The beginning of the first flat point represent the point where the gas become liquid, the extreme end of this point indicate the point where the liquid has started turning to liquid and that is the point of 275K. Thus at that point both phases are present.

5 0

4 years ago

Enzymes are catalysts in living things, including in the molds and bacteria that cause the spoiling reactions that decompose foo

jeka57 [31]

Answer: Discover ZEISS Solutions

Investigate soft materials like polymers, catalysts, coatings and chemicals to gain a better understanding of their properties. Analyze surface topography, chemical composition, tensile deformation and fracture patterns. Scroll down this page and discover microscopy characterization techniques and solutions from ZEISS enabling you to perform soft materials research in your lab efficiently.

5 0

3 years ago

Read 2 more answers

Photosynthesis allows plants to turn light energy into chemical energy by forming glucose from carbon dioxide and water: 6CO2(g)

dezoksy [38]

Answer:

305 g of CO₂

3.77 × 10⁵ kJ

Explanation:

Let's consider the global reaction for photosynthesis.

6 CO₂(g) + 6 H₂O(l) → C₆H₁₂O₆(g) + 6 O₂(g) ΔHrxn = 2802.8 kJ

A 1.70 lb sweet potato is approximately 73% water by mass. If the remaining mass is made up of carbohydrates derived from glucose (MW = 180.156 g/mol), how much carbon dioxide (MW = 44.01 g/mol) was needed to grow this sweet potato?

Let's consider the following relations:

The potato is 100%-73%=27% glucose by mass.
1 lb = 453.59 g.
6 moles of CO₂ produce 1 mole of glucose.
The molar mass of glucose is 180.156 g/mol.
The molar mass of carbon dioxide is 44.01 g/mol.

Then, for a 1.70 lb potato:

$1.70lbPotato.\frac{27lbGlucose}{100lbPotato} .\frac{453.59gGlucose}{1lbGlucose} .\frac{1molGlucose}{180.156gGlucose} .\frac{6molCO_{2}}{1molGlucose} .\frac{44.01gCO_{2}}{1molCO_{2}} =305gCO_{2}$

How much light energy does it take to grow the 1.70 lb. sweet potato if the efficiency of photosynthesis is 0.86%?

According to the enthalpy of the reaction, 2802.8 kJ are required to produce 1 mole of glucose. Then, for a 1.70 lb potato:

$1.70lbPotato.\frac{27lbGlucose}{100lbPotato} .\frac{453.59gGlucose}{1lbGlucose} .\frac{1molGlucose}{180.156gGlucose} .\frac{2802.8kJ}{1molGlucose} .\frac{1}{0.86\% } =3.77\times 10^{5} kJ$

7 0

3 years ago

What happens to the molecules when you heat a solid

Elena-2011 [213]

The molecules vibrate faster and space between atoms increase

8 0

4 years ago

Read 2 more answers

The prefab question someone help please !

lina2011 [118]

Answer: " 0.69 g / mL "

____________________________________________

Explanation:

______________________________________________

The "pre-lab question" given is:

_____________________________________________

"The volume of an unknown liquid is 15 ml, and the mass of the liquid and the graduated cylinder it is in is 55.2g. If the mass of the graduated cylinder is 44.8g , what is the density of the unknown liquid? " .

____________________________________________

Note: The volume of the unknown liquid is 15 mL ; regardless of whether or not the "unknown liquid" is in the graduated cylinder.

The density of the unknown liquid is measured in: "g / mL " ;

that is, "grams per mL" .

____________________________________________

Note: "D = m / V " ; that is; "Density = mass/ volume" ;

that is: ["Density = mass per 'unit volume' ]" .

____________________________________________

So; to find the density, "D" , of the "unknown liquid" ; we would have to find the "mass" of the "unknown liquid" by "subtracting" :

the "known mass of liquid when the liquid is not in the cylinder"; that is: " 44.8g" ; From:

the "known combined value of the: 'mass of the liquid PLUS the mass of the cylinder" ; that is: "55.2g" ;

→ " 55.2g - 44.8g = 10.4g " .

___________________________________________

So: " D = m / V " ; (55.2g - 44.8 g) / 15 mL " ;

= (55.2g - 44.8 g) / 15 mL " ;

= (10.4g) / 15mL ;

____________________________________________

Note that the "Density" = mass per "unit volume" ;

→ So: D = m / V ; in units of: " g / mL " (grams per millileter) ;

= (10.4g) / 15mL ;

= [ (10.4) / 15 } g/ mL ;

= 0.693333333333333.... g / mL ;

→ We round to "2 (two) significant figures" ;

→ since we have: "10.4 g / 15 mL " ;

and 15 mL is considered a measured/experimental value;

and: 10.4g is considered a measured/experimental value;

→ so, the least precise value; 15 mL (has only 2 (two) significant figures ;

compared to other value: 10.4g (which has 3 (three) significant figures;

→ so we shall round off to 2 (two) significant figures:

= 0.69 g / mL

____________________________________________

→ which is our answer: " 0.69 g / mL " .

____________________________________________

3 0

3 years ago