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3 years ago

What is the total mass of products formed when 16 grams of ch4?

1 answer:

3 0

When CH₄ is burnt in excess O₂ following products are formed,

CH₄ + 2 O₂ → CO₂ + 2 H₂O

According to equation 1 mole of CH₄ (16 g) reacts with 2 moles of O₂ to produce 1 mole of CO₂ and 2 moles of H₂O. Hence the products are,

1 mole of CO₂ and 2 moles of H₂O

Converting 1 mole CO₂ to grams;
As,
Mass = Moles × M.mass

Mass = 1 mol × 44 g.mol⁻¹

Mass = 40 g of CO₂

Converting 2 moles of H₂O to grams,

Mass = 2 mol × 18 g.mol⁻¹

Mass = 36 g of H₂O

Total grams of products;

Mass of CO₂ = 44 g
+ Mass of H₂O = 36 g
-------------
Total = 80 g of Product

Result:
80 grams of product is formed when 16 grams of CH₄ is burnt in excess of Oxygen.

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Concentrated hydrogen peroxide solutions are explosively decomposed by traces of transition metal ions (such as Mn or Fe): 2H2O2

zalisa [80]

Answer:

23.0733 L

Explanation:

The mass of hydrogen peroxide present in 125 g of 50% of hydrogen peroxide solution:

$Mass=\frac {50}{100}\times 125\ g$

Mass = 62.5 g

Molar mass of $H_2O_2$ = 34 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, moles are:

$moles= \frac{62.5\ g}{34\ g/mol}$

$moles= 1.8382\ mol$

Consider the given reaction as:

$2H_2O_2_{(aq)}\rightarrow2H_2O_{(l)}+O_2_{(g)}$

2 moles of hydrogen peroxide decomposes to give 1 mole of oxygen gas.

Also,

1 mole of hydrogen peroxide decomposes to give 1/2 mole of oxygen gas.

So,

1.8382 moles of hydrogen peroxide decomposes to give $\frac {1}{2}\times 1.8382 mole of oxygen gas. Moles of oxygen gas produced = 0.9191 molGiven: Pressure = 746 torr
The conversion of P(torr) to P(atm) is shown below:
[tex]P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 746 / 760 atm = 0.9816 atm

Temperature = 27 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (27 + 273.15) K = 300.15 K

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9816 atm × V = 0.9191 mol × 0.0821 L.atm/K.mol × 300.15 K

8 0

3 years ago

A. Explain, in terms of particles, why NaCl(s) does not conduct electricity.

yawa3891 [41]

Answer:

Ionic bonds hold charged particles in solid NaCl together, such that they are unable to move or conduct electricity.

Explanation:

Consider an electric current that flows through a conductor: charge moves in a uniform direction from one end of the conductor towards the other.

Thus, there are two conditions for a substance to conduct electricity:

The substance shall contain charged particles, and
These charged particles shall be free to move across the substance.

A conductor of electricity shall meet both requirements.

Now, consider the structure of solid NaCl $\rm NaCl\;(s)$ . NaCl is an ionic compound. It contains an ocean of oppositely charged ions:

Positive $\rm Na^{+}$ ions, and
Negative $\rm Cl^{-}$ ions.

Ions carry charge. Thus, solid NaCl contains charged particles and satisfies the first condition.

Inside solid NaCl $\rm NaCl\;(s)$ , electrostatic attractions ("ionic bonds") between the oppositely charged ions hold these ions in rigid ionic lattices. These ions are unable to move relative to each other. As a result, they cannot flow through the solid to conduct electricity. Under solid state, NaCl is unable to satisfy the second condition.

As a side note, melting NaCl into a liquid breaks the ionic bonds and free the ions from the lattice. Liquid NaCl is a conductor of electricity.

8 0

3 years ago

60 POINTS! PLEASE ANSWER!

Mumz [18]

I would have helped but I didn’t understand it sorry that I didn’t answer :(

6 0

2 years ago

Find the actual yield when the theatrical yield is 1.09g and percent yield is 90%.

ioda

Actual yield/Theoretical yield *100= Percentage yield. So Actual yield = Percentage yield*Theoretical yield.
Therefore actual yield= 90/100 * 1.09g = 0.98g

Actual yield: 0.98 g

3 0

2 years ago

Can you please help. I don't know how to do it.

Rainbow [258]

The area used to be covered by an ocean

3 0

3 years ago