What is the total mass of products formed when 16 grams of ch4?
1 answer:
When CH₄ is burnt in excess O₂ following products are formed, CH₄ + 2 O₂ → CO₂ + 2 H₂O According to equation 1 mole of CH₄ (16 g) reacts with 2 moles of O₂ to produce 1 mole of CO₂ and 2 moles of H₂O. Hence the products are, 1 mole of CO₂ and 2 moles of H₂O Converting 1 mole CO₂ to grams; As, Mass = Moles × M.mass Mass = 1 mol × 44 g.mol⁻¹ Mass = 40 g of CO₂Converting 2 moles of H₂O to grams, Mass = 2 mol × 18 g.mol⁻¹ Mass = 36 g of H₂OTotal grams of products; Mass of CO₂ = 44 g + Mass of H₂O = 36 g ------------- Total = 80 g of Product Result: 80 grams of product is formed when 16 grams of CH₄ is burnt in excess of Oxygen.
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