Expresar la cantidad de 620 000 con la sidra entera utilizando la potencia con base 10??

Bakit tinawag na pacific ring of fire ang mga bansa sa timog silangan asya at pasipiko? A. dahil sa aktibong bulkan B.dahil sa l

valkas [14]

Answer:

D

Explanation:

Sinagotan ko na to pero nakalimutan ko ans.

4 0

3 years ago

In every chemical reaction that produce energy, ____ react with ________ ?

GaryK [48]

Answer:

Acid reacts with water?

Explanation:

7 0

3 years ago

In an exothermic reaction, the bonding energy of the product is:

ahrayia [7]

I think the correct answer from the choices listed above is option A. In an exothermic reaction, the bonding energy of the product is less than the reactant because it is only at this condition that the energy is released by the reaction.

3 0

3 years ago

Read 2 more answers

HELP ME PLEASE ASAP. I'LL MARK YOU BRAINLIEST ITS NUMBER 23.

Ivanshal [37]

Answer:

The answer is A

Explanation:

5 0

3 years ago

CO2+2H2O=H3O^++HCO3^-

bekas [8.4K]

Answer:

Bronsted Lowry Theory

$CO_2$ is the acid

$H_2 O$ is the base

$H_3 O^+$ is the conjugate acid and

$HCO_3^-$ is the conjugate base

Explanation:

Bronsted Lowry Theory:

An acid is a substance that can donate one or more protons

A base is a substance which can accept one or more protons

Hydrogen atom which is neutral (No Charge) contains 1 positive proton, 1 negative electron and 0 neutral neutron.

Thus Hydrogen atom has no Charge and it is neutral.

When an hydrogen atom loses an electron, Hydrogen ion is formed, which will contain 1 positive proton and 0 negative electron and 0 neutral neutron.

Thus Hydrogen ion has a positive charge.

Hydrogen ion is also called as a proton since it has only 1 proton in it.

Hydrogen ion in water that is,

$H^++H_2O\Rightarrow H_3O^+$

$H_3O^+$ is called as Hydronium ion.

Acid loses H+ (proton) to form conjugate Base

Base gains H+ (proton) to form conjugate Acid

For example

Let us consider the example given in the question

$CO_2+2H_2 O>H_3 O^+ +HCO_3^-$ can be written as (removed 1 $H_2 O$ from both the sides )

$CO_2+H_2 O>H^++HCO_3^-$ or

$CO_2+H_2 O > H_2 CO_3$ reversing the equation

$H_2 CO_3+H_2 O>H_3 O^+ +HCO_3^-$

$H_2 CO_3$ is the acid which donates $H^+$ to form $HCO_3^-$

$H_2 O$ is the base which gains $H^+$ to form $H_3 O^+$

$HCO_3^-$ is the conjugate base and $H_3 O^+$ is the conjugate acid

So

$CO_2$ is the acid

$H_2 O$ is the base

$H_3 O^+$ is the conjugate acid and

$HCO_3^-$ is the conjugate base

(Answer)

5 0

3 years ago