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zaharov [31]
3 years ago
11

CO2+2H2O=H3O^++HCO3^-

Chemistry
1 answer:
bekas [8.4K]3 years ago
5 0

<u>Answer:</u>

<em>Bronsted Lowry Theory</em>

<em>CO_2 is the acid </em>

<em>H_2 O is the base </em>

<em>H_3 O^+ is the conjugate acid and </em>

<em>HCO_3^- is the conjugate base</em>

<u>Explanation:</u>

Bronsted Lowry Theory:

An acid is a substance that can donate one or more protons

A base is a substance which can accept one or more protons

Hydrogen atom which is neutral (No Charge) contains 1 positive proton, 1 negative electron and 0 neutral neutron.  

Thus Hydrogen atom has no Charge and it is neutral.

When an hydrogen atom loses an electron, Hydrogen ion is formed, which will contain 1 positive proton and 0 negative electron and 0 neutral neutron.

Thus Hydrogen ion has a positive charge.  

Hydrogen ion is also called as a proton since it has only 1 proton in it.

Hydrogen ion in water that is,  

H^++H_2O\Rightarrow H_3O^+

H_3O^+ is called as Hydronium ion.

Acid loses H+ (proton) to form conjugate Base

Base gains H+ (proton) to form conjugate Acid

For example  

Let us consider the example given in the question

CO_2+2H_2 O>H_3 O^+   +HCO_3^- can be written as (removed 1 H_2 O from both the sides )

CO_2+H_2 O>H^++HCO_3^- or  

CO_2+H_2 O  > H_2 CO_3 reversing the equation  

H_2 CO_3+H_2 O>H_3 O^+  +HCO_3^-

H_2 CO_3 is the acid which donates H^+ to form HCO_3^-

H_2 O is the base which gains H^+ to form H_3 O^+

HCO_3^- is the conjugate base and H_3 O^+ is the conjugate acid

So

CO_2 is the acid

H_2 O is the base

H_3 O^+ is the conjugate acid and

HCO_3^- is the conjugate base

(Answer)  

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8 0
3 years ago
For the following reaction, 9.30 grams of glucose (C6H12O6) are allowed to react with 13.8 grams of oxygen gas. glucose (C6H12O6
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Answer:

13.7 g of CO₂

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Explanation:

We convert the mass of the reactants to moles, in order to find out the limiting reactant and the excess reagent

9.30 g / 180 g/mol = 0.052 moles of glucose

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The equation is:  C₆H₁₂O₆(s) + 6O₂ (g) → 6CO₂ (g) + 6H₂O (l)

Ratio is 1:6. Let's consider this rule of three:

1 mol of glucose reacts with 6 moles of oxygen

Then, 0.052 moles of glucose must react with (0.052 . 6) /1 = 0.312 moles

We have 0.431 moles of oxygen and we only need 0.312 moles. This means that an amount of oxygen still remains after the reaction is complete:

0.431 - 0.312 = 0.119 moles. We convert the moles to mass:

0.119 mol . 32 g / 1mol = 3.81 g

In conclussion, the limiting reactant is the glucose.

6 moles of oxygen react with 1 mol of glucose

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Let's verify, the maximum amount of carbon dioxide that can be formed:

1 mol of glucose can produce 6 moles of CO₂

Therefore 0.052 moles of glucose will produce (0.052 . 6) /1 = 0.312 moles

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