The number of moles of gas present are 0.0054
<u>Explanation:</u>
Given-
Temperature, T = 100°C = 100 + 273 = 373K
Volume, V = 0.044L
Pressure, P = 3.81 atm
Moles of gas, n = ?
We know,
PV = nRT
R = 0.082 L.atm.K⁻¹.mol⁻¹
n = PV/RT
n = (3.81)(0.044)/(0.082)(373)
n = 0.0054 moles
Therefore, number of moles of gas present are 0.0054
Answer:
Given:
- Given mass of NaOH = 30 gram
- Molar mass of NaOH = 40 gram
- Volume = 2.40 litres
To find:
Molarity = ?
Solution:
<em>Molarity is nothing but the number of moles of solute dissolved in per litre of solution. given by </em><em>formula,</em>
Well the first thing you need to know is how much energy that 1g methanol release which is fixed value
Methanol CHOH is 17000 j/g
so the energy released when 10.0g of methanol is burned
=10x 17000
=170000 j
The answer would be:
C. The abuse will happen again regardless of how sorry the abuser seems to feel.
Hope this helps! :)
