Answer:
Uhh? You can't factor this!
Step-by-step explanation:
So.. we see that the last term, the constant, (the +5) is positive, which means the two terms (the a and b on the (x+a)(x+b) must be either both positive or both negative).
We try positive, and we end up with
(x+1)(x+5)
x^2 + x + 5x + 5
x^2 + 6x + 5
which is not what we want!
We try negative, and we end up with
(x-1)(x-5)
x^2 -x -5x +5
x^2 -6x +5
which is also not what we want!
This isn't factorable!
You can always complete the square or utilize the quadratic equation, but you can't factor it.
Hello,
x → field goals
y → foul shorts
x + y = 58
+( -2x + y = 92 )
--------------------------
-x + 0y = -34
x = 34
y = 58 - 34 = 24
Answer:
Step-by-step explanation:
Since the coordinates of P are (0, 1), this makes P the y-intercept of that line. The y-intercept exists where x = 0. And in the coordinate (0, 1), x does in fact equal 0.
Since the one coordinate given in Q is (?, 0), this means that Q is the x-intercept of the line. The x-intercept exists where y = 0. And in the coordinate (?, 0), y does in fact equal 0. So in order to solve for the x coordinate of Q, we plug in a 0 for y and solve for x:
3(0) - 4x = 12 and
-4x = 12 so
x = -3
Turn equation around:
7u-9-12u=26
Combine like terms:
-12u+7u=-5u
This turns equation into:
-5u-9=26
Add -9 to both sides:
-5u-9=26
+9=+9 - and + cancel out
-5u=35
Divide by -5 to get “u” by itself:
-5u=35
———— -5 And -5 cancel making
-5 =-5 “u” By itself
u= -7
Hope this helps!
