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Elanso [62]
3 years ago
10

9. How does the length of the hypotenuse in a right triangle relate to the lengths of the legs? (2 points)

Physics
2 answers:
konstantin123 [22]3 years ago
6 0
<span>The pythagorean theorem addresses the length of the hypotenuse in relation to the length of the legs. The square root of the length of the hypotenuse is equal to the sum of one leg squared plus the other leg squared. In other words, A squared plus B squared equals C squared where A and B are the lengths of the legs of the triangle and C is the length of the hypotenuse.</span>
seropon [69]3 years ago
4 0

Answer:

hypotenuse² = base² +height²

Explanation:

Let us suppose a right angled triangle having b as base, h as hypotenuse and p as perpendicular distance.

The relation between the length of legs, the base and the hypotenuse is called Pythagoras theorem. It is given by :

h^2=b^2+p^2

or

hypotenuse² = base² +height²

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larisa [96]

Answer:21

Explanation:

4 0
2 years ago
An elevator supported by a single cable descends a shaft at a constant speed. The only forces acting on the elevator are the ten
VikaD [51]

Answer:

C. The net work done by the two forces is zero joules.

Explanation:

Work (W) is defined as the product of force F) by the distance (d)the body travels due to this force.  

W= F*d Formula ( 1)

The work is positive (W+) if the force has the same direction of movement of the object.  

The work is negative (W-) if the force has the opposite direction of the movement of the object.

The component of the force that performs work must be parallel to the displacement.  

Calculation of the forces

We apply Newton's second law:

∑F = m*a

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

∑F = m*a  

a = 0 because the elevator moves at constant speed.

∑F=0

T-W = 0

T = W  

Calculation of work done by the forces

W₁ :  work done by the gravity= (+ W*d ) J

W₂ : work done by the tension force=( -T*d) J

Net work done by the two forces(W₁-W₂):

W₁= W₂ .because T = W  

W₁-W₂ =0

3 0
3 years ago
Two pulses move in opposite directions on a string and are identical in shape except that one has positive displacements of the
Leni [432]

(c) When the two pulses completely overlap on the string forms a straight line.

A single disturbance that travels via a transmission medium is referred to as a pulse. This medium might be formed of stuff or a vacuum, and it might be endlessly large or finite in size.

Consider two pulses that are identical in shape and proceed in opposite directions along a string, with the exception that one has positive displacements of the string's elements while the other has negative displacements.

On the string, the two pulses blend together completely.

The pulses completely balance one another out in terms of removing string elements from equilibrium, yet the string still moves. Shortly after the string is once again shifted, the pulses will have passed each other.

The correct option is (c)

Learn more about pulse here:

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6 0
1 year ago
One property that makes electromagnetic waves differ from other types of waves is that they can
IgorC [24]
Electromagnectic Waves Travel In A Vacuum
4 0
3 years ago
Read 2 more answers
If you observe an object in the universe that is roughly 8 megaparsecs in size, what is the object most likely to be?
Dmitrij [34]

E. Galaxy Cluster

Explanation:

A galaxy cluster, or cluster of galaxies, is a structure that consists of anywhere from hundreds to thousands of galaxies that are bound together by mutual gravity.

A megaparsec is a million parsecs and there are about 3.3 light years in a mega-parsec. Parsec is rather a natural distance unit for astronomers. The standard abbreviation of a mega-parsec is Mpc.

A parsec is approximately 3.09 x 1016 meters, a megaparsec is about 3.09 x 1022 meters.

Hence, 8 megaparsecs is gigantic size and that can be only of a galaxy cluster consisting of hundreds and thousands of galaxies bounded together.

Keywords: galaxies, parsec, megaparsec, galaxy cluster

Learn more about galaxy clusters and astronomical units from:

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4 0
3 years ago
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