Sorry if this answer is a bit late...
We know that the volume of the water is 0.5 cube meters.
The density of water is 1.000 g/m^3 (that's the real density of water... maybe typos?)
The density of ice is 0.900 g/m^3 (that's the approximate density of ice)
First, let's multiply the volume of water by the density of the water to get the mass, since we know that the mass does not change with the ice gets frozen.
0.5 * 1.000 = 0.500 g
Now, let's divide that by the density of ice to get the volume of the ice.
0.500 / 0.900 = 5/9 cube meters
≈ 0.556 cube meters.
The volume of the ice is 5/9 or 0.556 cube meters.
Have an awesome day! :)
Answer:
Explanation:
The energy of a photon is given by:
where
is the Planck constant
is the speed of light
is the wavelenght of the photon
For the microwave photons in this problem,
so their energy is
Answer:
force acting on the parent = 25 N .
Explanation:
According to third law of Newton , there is equal and opposite reaction to every action . Here force by the parent on child is action and the force by child on parent is reaction . The former is given as 25 N so force by child on parent will also be 25 N .
Answer is 25 N .
Answer:
The maximum displacement of the mass m₂
Explanation:
Kinetic Energy (K) = 1/2mv²
Potential Energy (P) = mgh
Law of Conservation of energy states that total energy of the system remains constant.
i.e; Total energy before collision = Total energy after collision
This implies that: the gravitational potential energy lost by m₁ must be equal to sum of gravitational energy gained by m₂ and the elastic potential energy stored in the spring.
d = maximum displacement of the mass m₂
Answer:
= 625 nm
Explanation:
We now that for
for maximum intensity(bright fringe) d sinθ=nλ n=0,1,2,....
d= distance between the slits, λ= wavelength of incident ray
for small θ, sinθ≈tanθ= y/D where y is the distance on screen and D is the distance b/w screen and slits.
Given
d=1.19 mm, y=4.97 cm, and, n=10, D=9.47 m
applying formula
λ= (d*y)/(D*n)
putting values we get
on solving we get
= 625 nm