Answer:
A
Explanation:
always more reactants than products
Answer:
Time take to deposit Ni is 259.02 sec.
Explanation:
Given:
Current 
A
Faraday constant 
Molar mass of Ni 
Mass of Ni 
g
First find the no. moles in Ni solution,
Moles of Ni 
mol
From the below reaction,
⇆ 
Above reaction shows "1 mol of 
requires 2 mol of electron to form 1 mol of "
So for finding charge flow in this reaction we write,
Charge flow 
C
For finding time of reaction,
Where 
charge flow
sec
Therefore, time take to deposit Ni is 259.02 sec.
Solubility rules state that group one metals and Nitrates are always soluble. Rubidium is a group one metal, so Rubidium Nitrate, RbNO3, is soluble.
Answer:
V₂ = 946.72 mL
Explanation:
Given data;
Initial pressure = 0.926 atm
Initial volume = 457 mL
Temperature = constant = 29.5°C
Final pressure = 0.447 atm
Final volume = ?
Solution:
The given problem will be solved through the Boyle's law,
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
by putting values,
P₁V₁ = P₂V₂
0.926 atm × 457 mL = 0.447 atm × V₂
V₂ = 423.18 atm. mL/ 0.447 atm
V₂ = 946.72 mL
Answer is: 3,3 mol of <span>nitrous oxide gas is produced in this chemical reaction.
</span>Chemical reaction: N₂ + O₂ → 2NO.
n(N₂) = 1,65 mol.
n(NO) = ?
from reaction n(N₂) : n(NO) = 1 : 2.
1,65 mol : n(NO) = 1 : 2.
n(NO) = 3,3 mol.
n - amount of substance.
