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4 years ago

Which tool would BEST be used for measuring the temperature of the classroom?

2 answers:

6 0

Most people would say thermometer, but really the answer is a laser thermometer because a thermometer would take at least like 30 minutes to get a temperature, while a laser thermometer would take 5 seconds. Press the trigger and the laser beam hits a wall, or whatever you wanna take the temp. of and you got the temp.

Hope it helps✌

Anettt [7]4 years ago

4 0

The answer is thermometer

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Consider the generic reaction: 2 A(g) + B(g) → 2 C(g). If a flask initially contains 1.0 atm of A and 1.0 atm of B, what is the

irina1246 [14]

Answer:

b. 1.5 atm.

Explanation:

Hello!

In this case, since the undergoing chemical reaction suggests that two moles of A react with one moles of B to produce two moles of C, for the final pressure we can write:

$P=P_A+P_B+P_C$

Now, if we introduce the stoichiometry, and the change in the pressure $x$ we can write:

$P=1.0-2x+1.0-x+2x$

Nevertheless, since the reaction goes to completion, all A is consumed and there is a leftover of B, and that consumed A is:

$x=\frac{1.0atm}{2}=0.5atm$

Thus, the final pressure is:

$P=1.0-2(0.5)+1.0-(0.5)+2(0.5)\\\\P=1.5atm$

Therefore the answer is b. 1.5 atm.

Best regards!

3 0

3 years ago

A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a

svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = $62.364\text{ L. Torr }mol^{-1}K^{-1}$

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

$51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol$

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g$

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0

3 years ago

Name the following compound: HNO3 Hydrogen nitrate Hydrogen nitrite Nitric acid Nitrous acid

wariber [46]

The compound HNO3 is called nitric acid.

HNO3 is a covalent compound and a strong acid which ionizes in water into H+ (proton) and NO3- (nitrate ion).

HNO3 (aq) ↔ H+(aq) + NO3-(aq)

Ans: HNO3 = Nitric Acid

[On a side note: Nitrous acid is HNO2]

7 0

3 years ago

Read 2 more answers

What is the mass number of a atom that has 4 protons 4electrons 5neutrons

user100 [1]

Answer:

<h3><em>Please make sure to re-write this on your own so your teacher doesn't think that your cheating!</em></h3>

Explanation:

A neutral atom will have the same number of electrons does protons. Since it has 4 protons, it must have an atomic number of 4. (That will make it beryllium.) Since it has 4 protons and 5 neutrons, it has a mass number of 9.

So the answer is 9

4 0

3 years ago

How many moles are there in 3.612 x 1024 molecules of CaO?

melamori03 [73]

The number of moles in 3.612 x 10²⁴ molecules of CaO is 6 moles.

<h3>Number of moles in the molecules</h3>

The number of moles in 3.612 x 10²⁴ molecules of CaO is calculated as follows;

6.02 x 10²³ molecules = 1 mole

3.612 x 10²⁴ molecules = ?

= (3.612 x 10²⁴ ) / (6.02 x 10²³ )

= 6 moles

Thus, the number of moles in 3.612 x 10²⁴ molecules of CaO is 6 moles.

Learn more about number of moles here: brainly.com/question/15356425

3 0

2 years ago