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Eva8 [605]
3 years ago
9

Which statement about a right triangle is NOT true?

Physics
2 answers:
Alex787 [66]3 years ago
6 0

Answer:

The square of the hypotenuse is equal to the sum of the squares of the other two lengths.

Explanation:

only one that made sense

kiruha [24]3 years ago
4 0

Answer:

The sum of the length of the two legs is equal to the length of the hypotenuse.

Explanation:

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The resistance of an object to change its dynamic state called​
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Inertia is the correct answer!
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PERIOD OF THE LEG The period of the leg can be approximated by treating the leg as a physical pendulum, with a period of Equatio
Lesechka [4]

Answer:

Explanation:

We can see from the question that

        T 2\pi\sqrt{\frac{I}{mgh} }

  and  I = \frac{ml^2}{3}

           m = 16% of  67kg

 =>      m =10kg

      from the question  l =48% of 1.83m

 Substituting this into the equation

                 I = \frac{10.72 * (0.8784)^2}{3}

        =>   I = 2.7571 \  kg m^2

                      h = 0.5 * L

                       h = 0.5 * 0.8784

                     h = 0.4392m

From the equation above

      T  =  2 \pi \sqrt{\frac{2.7571}{10 .72 * 9.81 * 0.4392} }

       T = 1,534\ sec

           

4 0
3 years ago
TIMED! URGENT! REALLY APPRECIATE HELP!! TYSM!!!!!!
Diano4ka-milaya [45]
The answer is 27.03 I just multiplied the two numbers
3 0
3 years ago
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Which of the following is the equivalent resistance of the circuit shown?
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3 years ago
The hydronium ion concentration of your gastric fluid is 1.0 x 10^-2. you drink a tablespoon of milk of magnesia, which raises t
slamgirl [31]

Answer:

[OH⁻] = 1 × 10⁻¹¹ mol/dm³

Explanation:

Since the hydronium ion concentration of the gastric fluid is [H₃O]⁺ = 1.0 × 10⁻².

The pH at this point is pH = -log₁₀[H₃O]⁺ = -log₁₀[1.0 × 10⁻²] = 2

When milk of magnesia is added, the pH increases by one unit, so the new pH is 1 + 2 = 3

Since pH + pOH = 14, then pOH = 14 - pH = 14 - 3 = 11

The hydroxide ion concentration of the fluid is gotten from

pOH = -log₁₀[OH⁻]

11 = -log₁₀[OH⁻]

-11 = log₁₀[OH⁻]

taking antilog

[OH⁻] = 1 × 10⁻¹¹ mol/dm³

7 0
4 years ago
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