<span>when an object is at rest, it does not travel any distance i.e. distance = 0.
hence speed = 0, for an object at rest.</span><span>
</span>
Find the v first by using 3.14x0.22x2.16 div. 41g
Answer:
Explanation:
Given
Charge of first Particle
Charge of second Particle
distance between them
magnetic field due to first charge at mid-way between two charged particles is
(away from it)
Electric field due to
(towards it)
(away from first charge)
We can obtain the answer easily if we assume the gas here is an ideal gas. We can use t he expression:
PV = nRT
we set nR/V = k
P/T = k
P1/T1 = P2/T2
when P2 = 3P1
P1/10 = 3P1/T2
T2 = 30 degrees Celsius
Answer:
Mass of the box = 0.9433 kg
Explanation:
Mass of racket-ball = 0.00427 kg
Velocity of racket-ball before collision = 22.3 m/s
Velocity of racket-ball after collision with box = -11.5 m/s
[Since ball is bouncing back, so velocity is taken negative.]
Velocity of the box before collision = 0 m/s
<em>[Since the box is stationary, so velocity is taken zero]</em>
Velocity of box moving forward after collision = 1.53 m/s
To find the mas of the box .
By law of conservation of momentum we have:
Momentum before collision = Momentum after collision
This can be written as:
We can plugin the given value to find
Adding both sides by 0.4911
Dividing both sides by 1.53.
∴ kg
Mass of the box = 0.9433 kg (Answer)