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Effectus [21]
3 years ago
8

What is the kinetic energy of a 24-kg mass that is moving with a velocity of 2 m/s?

Physics
2 answers:
Anton [14]3 years ago
3 0

Answer:

1/2mv^2

1/2*24*2^2

answer=48

Alina [70]3 years ago
3 0

Answer:

48 J

Explanation:

Kinetic energy can be found using the following formula:

KE=\frac{1}{2}mv^2

where <em>m </em>is the mass in kilograms and <em>v </em>is the velocity in m/s.

We know the mass is 24 kilograms and the velocity is 2 m/s Therefore, substitute 24 in for <em>m </em>and 2 in for <em>v. </em>

<em />KE=\frac{1}{2}*24*2^2<em />

Evaluate the exponent first. 2^2 is the same as multiply 2, 2 times.

2^2=2*2=4

KE=\frac{1}{2}*24*4

Multiply 24 and 4

KE=\frac{1}{2} *96

Multiply 96 and 1/2, or divide 96 by 2.

KE=48

Add appropriate units. Kinetic energy uses Joules, or J

KE=48 Joules

The kinetic energy is 48 Joules

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2. A hanging wind-chime on a calm day would have kinetic or potential energy?
rjkz [21]

Answer:

it would have potential energy

7 0
3 years ago
Yashoda prepares some lime juice on a hot day. She adds 80 g of ice at a temperature of 0°C to 0.32 kg of lime juice. The temper
Vikentia [17]

Answer:

Explanation:

a )

hear energy required to melt 1 g of ice = 340 J ,

hear energy required to melt 80 g of ice = 340 x 80  J = 27220 J .

b ) energy gained by the melted ice ( water at O°C ) = m ct

where m is mass of water , s is specific heat and t is rise in temperature

= 80 x 4.2 x ( 8°C - 0°C)

= 2688 J .

c )

energy lost by lime juice = energy gained by ice and water

= 27220 J + 2688 J .

= 29908 J .

d )

Let specific heat required be S

Heat lost by lime juice = M S T

M is mass of lime juice , S is specific heat , T is decrease in temperature

= 320 g x S x ( 29 - 8 )°C

= 6720 S

For equilibrium

Heat lost = heat gained

6720 S = 29908 J

S = 4.45 J /g °C .

4 0
3 years ago
Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr
d1i1m1o1n [39]
For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km
3 0
4 years ago
Read 2 more answers
Assume that the function x(t) represents the length of tape that has unwound as a function of time. find θ(t), the angle through
bekas [8.4K]
We know that arc length (x(t)) is given with the following formula:
x(t)=\theta(t) r
Where r is the radius of the barrel. We must keep in mind that as barrel rolls its radius decreases because less and less tape is left on it.
If we say that the thickness of the tape is D then with every full circle our radius shrinks by d. We can write this down mathematically:
r(\theta)=r_0-\frac{D\cdot \theta}{2\pi}
When we plug this back into the first equation we get:
x(t)=\theta(r_0-\frac{D\theta}{2\pi}})\\ \frac{D\theta^2}{2\pi}-\theta r_0+x(t)=0\\
We must solve this quadratic equation.
The final solution is:
\theta=\frac{\pi r_0+\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D},\:\theta=\frac{\pi r_0-\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D}
It is rather complicated solution. If we asume that the tape has no thickness we get simply:
x(t)=\theta(r_0-\frac{D\theta}{2\pi}});D=0\\&#10;x(t)=\theta r_0\\&#10;\theta(t)=\frac{x(t)}{r_0}

8 0
4 years ago
The two forces in each pair can either both act on the same body or they can act on different bodies. The two forces in each pai
kotykmax [81]

Answer: The given statement is false.

Explanation:

According to Newton's third law of motion, every action has an equal and opposite reaction. So, when we apply force in one direction on an object then the object also applies a force in the opposite direction.

Hence, it is true that two forces in each pair of forces act in opposite directions.

For example, when we push a wooden box of 20 kg in the forward direction then the box will also apply a force in the opposite direction.

But the statement two forces in each pair can either both act on the same body or they can act on different bodies is false.

5 0
3 years ago
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