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2 years ago

What is the kinetic energy of a 24-kg mass that is moving with a velocity of 2 m/s?

Physics

2 answers:

Anton [14]2 years ago

3 0

Answer:

1/2mv^2

1/2*24*2^2

answer=48

Alina [70]2 years ago

3 0

Answer:

48 J

Explanation:

Kinetic energy can be found using the following formula:

$KE=\frac{1}{2}mv^2$

where m is the mass in kilograms and v is the velocity in m/s.

We know the mass is 24 kilograms and the velocity is 2 m/s Therefore, substitute 24 in for m and 2 in for v.

$KE=\frac{1}{2}*24*2^2$

Evaluate the exponent first. 2^2 is the same as multiply 2, 2 times.

2^2=2*2=4

$KE=\frac{1}{2}*24*4$

Multiply 24 and 4

$KE=\frac{1}{2} *96$

Multiply 96 and 1/2, or divide 96 by 2.

$KE=48$

Add appropriate units. Kinetic energy uses Joules, or J

$KE=48 Joules$

The kinetic energy is 48 Joules

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Displacement of ball (S) = 0.665 m

Initial velocity ( $v_d$ ) = 4.95 m/s(Upward direction)

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Using equation of motion, we have:

$v_{up}^2=v_d^2+2aS\\\\v_{up}=\pm\sqrt{v_d^2+2aS}\\\\v_{up}=\pm\sqrt{24.5+2\times -9.8\times 0.665}\\\\v_{up}=\pm\sqrt{10.966}=\pm3.31\ m/s$

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Impulse = Final momentum - Initial momentum

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