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Artemon [7]
2 years ago
11

What is the eulerian description of fluid motion how does it differ from the lagrangian description?

Physics
1 answer:
Alex_Xolod [135]2 years ago
3 0

Kinematics : Study of motion

Fluid kinematics : study of how fluid flows and how to describe its motion.

There are two ways to describe fluid motion

one is Eulerian, where the variations are described at all fixed stations as a function of time.

the other is Lagrangian, in which one follows all fluid particles and describes the variations around each fluid particle along its trajectory.

<u>DIFFRENCE  BETWEEN  LAGRANGIAN AND EULERIAN:</u>

1.Both Lagrangian and Eulerian describes time variation.

2. Eulerian describes the rate of change in one point of space

Lagrangian descries rate of change of a property of material system.

To know more about the Lagrangian and Eulerian :\brainly.com/question/14944792

#SPJ4

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Answer:

Hey

(note you have forgotten your diagram so this may not be what you where hoping for.)

The important discovery that galilao made was that he proved that <em><u>all objects no matter their mass fall at the same rate.</u></em>

That is to say that a bowling ball falls at the same rate as a truck.

4 0
3 years ago
The force of friction between an object and the surface upon which it is sliding is 14N and the coefficient of friction between
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Answer:

14 x 0.27 = 3.78 is your answer

Explanation:

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Which instrument is not used to measure air pressure
Virty [35]
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A generator makes electricity from _____ A. Chemical reactions B. Friction C. Kinetic energy D. Heat
coldgirl [10]

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7 0
3 years ago
Read 2 more answers
A 14,700 N car is traveling at 25 m/s. The brakes are applied suddenly, and the car slides to a stop. The average braking force
Vlada [557]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

vo = 25 m/sec 
<span>vf = 0 m/sec </span>
<span>Fμ = 7100 N (Force due to friction) </span>
<span>Fg = 14700 N </span>
<span>With the force due to gravity, you can find the mass of the car: </span>
<span>F = ma </span>
<span>14700 N = m (9.8 m/sec²) </span>
<span>m = 1500 kg </span>
<span>Now, we can use the equation again to find the deacceleration due to friction: </span>
<span>F = ma </span>
<span>7100 N = (1500 kg) a </span>
<span>a = 4.73333333333 m/sec² </span>
<span>And now, we can use a velocity formula to find the distance traveled: </span>
<span>vf² = vo² + 2a∆d </span>
<span>0 = (25 m/sec)² + 2 (-4.73333333333 m/sec²) ∆d </span>
<span>0 = 625 m²/sec² + (-9.466666666667 m/sec²) ∆d </span>
<span>-625 m²/sec² = (-9.466666666667 m/sec²) ∆d </span>
<span>∆d = 66.0211267605634 m </span>
<span>∆d = 66.02 m</span>
7 0
3 years ago
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