All categories

2 years ago

What is the eulerian description of fluid motion how does it differ from the lagrangian description?

Physics

1 answer:

Alex_Xolod [135]2 years ago

3 0

Kinematics : Study of motion

Fluid kinematics : study of how fluid flows and how to describe its motion.

There are two ways to describe fluid motion

one is Eulerian, where the variations are described at all fixed stations as a function of time.

the other is Lagrangian, in which one follows all fluid particles and describes the variations around each fluid particle along its trajectory.

<u>DIFFRENCE BETWEEN LAGRANGIAN AND EULERIAN:</u>

1.Both Lagrangian and Eulerian describes time variation.

2. Eulerian describes the rate of change in one point of space

Lagrangian descries rate of change of a property of material system.

To know more about the Lagrangian and Eulerian :\brainly.com/question/14944792

#SPJ4

You might be interested in

Which two particles are present in the nucleus of an atom? Electrons and neutrons Electrons and molecules 1 TH O Protons and neu

aleksandrvk [35]

Answer:

Protons and neutrons

Explanation:

8 0

3 years ago

Please helps me with this question..

Alenkasestr [34]

1) S.I. Unit for electric current = "Ampere"

2) S.I. Unit for resistance = "Ohm"

3) S.I. Unit for potential difference = "Volt"

Hope this helps!

8 0

3 years ago

A satellite that goes around the earth once every 24 hours (86,400 s) is called a geosynchronous satellite. If a geosynchronous

Olegator [25]

Answer:

42244138.951 m

Explanation:

G = Gravitational constant = 6.667 × 10⁻¹¹ m³/kgs²

r = Radius of orbit from center of earth

M = Mass of Earth = 5.98 × 10²⁴ kg

m = Mass of Satellite

The satellite revolves around the Earth at a constant speed

Speed = Distance / Time

The distance is the perimeter of the orbit

$v=\frac{2\pi \times r}{24\times 3600}$

The Centripetal force of the satellite is balanced by the universal gravitational force

$m\frac{v^2}{r}=\frac{GMm}{r^2}\\\Rightarrow \frac{\left(\frac{2\pi \times r}{24\times 3600}\right)^2}{r}=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}}{r^2}\\\Rightarrow \left(\frac{2\pi \times r}{24\times 3600}\right)^2=6.667\times 10^{-11}\times 5.98\times 10^{24}\\\Rightarrow r^3=\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\\\Rightarrow r=\left(\frac{6.667\times 10^{-11}\times 5.98\times 10^{24}\times (24\times 3600)^2}{(2\pi)^2}\right)^{\frac{1}{3}}\\\Rightarrow r=42244138.951\ m$

The radius as measured from the center of the Earth) of the orbit of a geosynchronous satellite that circles the earth is 42244138.951 m

6 0

3 years ago

Describe the motion of a swing that requires 6 seconds to complete one cycle. What is its period and the frequency? Round to the

shutvik [7]

Period = 6 seconds and $frequency = 0.167Hz$ .

<u>Explanation:</u>

We have , the motion of a swing that requires 6 seconds to complete one cycle. Period is the amount of time needed to complete one oscillation . And in question it's given that 6 seconds is needed to complete one cycle. Hence ,Period of the motion of a swing is 6 seconds . Frequency is the number of vibrations produced per second and is calculated with the formula of $\frac{1}{t}$ . SI unit of frequency is Hertz or Hz. We know that time period is 6 seconds so frequency = $\frac{1}{t}$