Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.

1 answer:

8 0

we are given the data of lengths 5 and 10 of an acute triangle and is asked to detemine the length of the third side. In this case, it cannot be 4 since the sum of 5 and 4 does not exceed the longest one. Sides 6 and 11 result to an obtuse triangle. Answer is B.5

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Help please :( thank u

snow_tiger [21]

Answer:

he needs to know the width!!!

Step-by-step explanation:

since length multiplied by the width equals area,

so since the length is given, the width is needed

8 0

3 years ago

Write the equation of a Line that is perpendicular to y=5/2x+3 and passes

koban [17]

Answer:

Step-by-step explanation:

Slope of perpendicular lines = -1

y = 5/2x + 3

$m_{1}=\frac{5}{2}\\\\m_{1}*m_{2}=-1\\\\$

$m_{2}=$ -1 ÷ $m_{1}$

= $-1*\frac{2}{5}=\frac{-2}{5}$

(-3 , -5)

Equation of the required line: y - y₁ = m(x -x₁)

y - [5] = $\frac{-2}{5}(x - [-3])\\$

$y+5=\frac{-2}{5}x + 3*\frac{-2}{5}\\\\y+5=\frac{-2}{5}x-\frac{6}{5}\\\\ y =\frac{-2}{5}x-\frac{6}{5}-5\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{5*5}{1*5}\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{25}{5}\\\\\\ y=\frac{-2}{5}x-\frac{31}{5}$