Answer:
Step-by-step explanation:
Given the equation
4x+12y=72
The equation of a line can written as
y=mx+c
Where m is the slope
And c is the intercept on y axis
Then, we need to write the equation given in the form of equation of a line (y=mx+c), by making y subject of the formula
4x+12y=72
12y=-4x+72
Divide through by 12
y=-4x/12 + 72/12
y=-⅓x+6
Then, comparing with equation of a line shows that
m=-⅓ and c=6
So we need to get another linen that is perpendicular to this line and passes through the point (-9,6)
The slope of the line perpendicular to another line is given as
m1=-1/m2
Then, m1=-1÷-⅓
Then, the slope of the perpendicular line is 3
Then, m=3
So apply this to equation of the line
y=mx+c
Then, y=3x+c
So to know c, we will insert the point given(-9,6), x=-9 and y=6
y=3x+c
6=3(-9)+c
6=-27+c
Then, c=6+27
c=33
Then, the equation of line becomes
y=3x+33
Answer:
773 and 869 and 703 on any day
Answer:
( - infinity, 4) thats the range hope it helps.
B. (6, -8)
First, you need to figure out the slope of the line
(y1 - y2) / (x1 - x2)
After substituting points D(-3, 4) A(3, -4)
[4 - (-4)] / (-3 - 3)
(8) / (-6)
The slope of the line is -8/6 or -4/3 simplified
Then you can put it in point slope form:
(y - y1) = m(x - x1)
(y - y1) = -4/3(x - x1)
The point that I am using for point slope form is A(3, -4)
[y - (-4)] = -4/3(x - 3)
y + 4 = -4/3(x - 3)
Next you have to simplify the equation so that y is isolated
y + 4 = -4/3(x - 3)
First distribute the -4/3
y + 4 = -4/3(x) + (-4/3)(-3)
y + 4 = -4/3x + 4
Subtract 4 on both sides
y + 4 - 4 = -4/3x + 4 - 4
y = -4/3x
Now that you have y = -4/3x, you can substitute the values until one of them makes the equation equal
For example) (6, -8)
-8 = -4/3(6)
-8 = -8
So since (6, -8) fits in the slope intercept equation, it must me collinear with points A and D
~~hope this helps~~
