All categories

3 years ago

What is the structure of cf2br2

1 answer:

3 0

The structure of CF2Br2 has 2 structures total because there is one isomer of the molecule.

F F

l l

F---C---Br and Br---C---Br with 6 e- on each of the outer species

l l

Br F

You might be interested in

A chemical reaction produces formaldehyde, with a chemical formula of CH2O. Carbon is in group 4A, Oxygen is in group 6A, and Hy

steposvetlana [31]

Answer:

Explanation:

carbon in group 4A needs 4 more electrons to be stable

hydrogen in group 1A has one electron needs 1 more t o be stale

oxygen in group 6A has 6 and needs 2 more to be stable

They all obtain this by sharing electrons 8 around C &O, 2 around H

H : C: H

:O:

5 0

2 years ago

Covalent bonding is the ____ of electrons

taurus [48]

Answer: sharing

Reason: They do this to gain stability. The reason they don’t actually transfer is because the difference in electronegativity values are above a certain value.

8 0

3 years ago

(b) The conductivity of a 0.01 mol dm–3 solution of a monobasic organic acid in water is 5.07 × 10–2 S m–1. If the molar conduct

Zarrin [17]

Explanation:

The given data is as follows.

$\Lambda^{o}_{m}$ (NaCl) = $1.264 \times 10^{-2}$

$\Lambda^{o}_{m}$ (H-O=C-ONO) = $1.046 \times 10^{-2}$

$\Lambda^{o}_{m}$ (HCl) = $4.261 \times 10^{-2}$

Conductivity of monobasic acid is $5.07 \times 10^{-2} S m^{-1}$

Concentration = 0.01 $mol/dm^{3}$

Therefore, molar conductivity ( $\Lambda_{m}$ ) of monobasic acid is calculated as follows.

$\Lambda_{m} = \frac{conductivity}{concentration}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol/dm^{3}}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol \times 10^{3}}$

= $5.07 \times 10^{-3} S m^{2} mol^{-1}$

Also, $\Lambda^{o}_{m}$ = $\Lambda^{o}_{m}_{(HCl)} + \Lambda^{o}_{m}_{(H-O=C-ONO)} - \Lambda^{o}_{m}_{(NaCl)}$

= $4.261 \times 10^{-2} + 1.046 \times 10^{-2} - 1.264 \times 10^{-2}$

= $4.043 \times 10^{-2} S m^{2} mol^{-1}$

Relation between degree of dissociation and molar conductivity is as follows.

$\alpha = \frac{\Lambda_{m}}{\Lambda^{o}_{m}}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{4.043 \times 10^{-2} S m^{2} mol^{-1}}$

= 0.1254

Whereas relation between acid dissociation constant and degree of dissociation is as follows.

K = $\frac{c \times \alpha^{2}}{1 - \alpha}$

Putting the values into the above formula we get the following.

K = $\frac{c \times \alpha^{2}}{1 - \alpha}$

= $\frac{0.01 \times (0.1254)^{2}}{1 - 0.1254}$

= $0.017973 \times 10^{-2}$

= $1.7973 \times 10^{-4}$

Hence, the acid dissociation constant is $1.7973 \times 10^{-4}$ .

Also, relation between $pK_{a}$ and $K_{a}$ is as follows.

$pK_{a} = -log K_{a}$

= $-log (1.7973 \times 10^{-4})$

= 3.7454

Therefore, value of $pK_{a}$ is 3.7454.

3 0

3 years ago

Brainliets and a lot of points to ever answers all questions and get all right

Juli2301 [7.4K]

Answer:

try at your own

4 0

3 years ago

Read 2 more answers

A reaction will most likely occur if the colliding particles have the proper

fenix001 [56]

Answer: a rection will most likely occur if the colliding partilces have the proper orientation and energy.

The reactions occur becasue the molecules collide.

But not all the collisions result in a reaction.

The collisions have to meet some requirements.

Two of the basic requirements is that the collision has enough energy to overcome the activation energy and that the molecules collide in the riight way.

When two molecules react it is necessary that one element of one of the molecules interact when a specific element or group in the other molecule. That is the orientation must be the right one.

Collisions that to not have the proper orientation or enough energy will not cause reaction (changes in the bonds of the molecules).

4 0

3 years ago