Identify a chemical reagent used in this experiment that can be used to distinguish solid CaCl2 (soluble) from solid CaCO3 (inso
2 answers:
Answer: Silver nitrate is the chemical reagent used to distinguish.
Explanation:
Dissolve both compounds in water. And add silver nitrate to that solution.
1. In case of calcium chloride
The calcium chloride is soluble in water and thus forms ions in aqueous solution.The chloride ions present in the solution react with silver ions of silver nitrate to give white color precipitate of silver chloride.
2. in case of calcium carbonate.
The calcium carbonate is poorly soluble in water. Since, it doesn't get dissolved in water.
When silver nitrate is added there will be no formation of any precipitate.
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Answer:
lattice parameter = 5.3355x10^-8 cm
atomic radius = 2.3103x10^-8 cm
Explanation:
known data:
p=0.855 g/cm^3
atomic mass = 39.09 g/mol
atoms/cell = 2 atoms
Avogadro number = 6.02x10^23 atom/mol
a) the lattice parameter:
Since potassium has a cubic structure, its volume is equal to:
v = [(atoms/cell)x(atomic mass)/(p)x(Avogadro number)]
substituting values:
v =[(2)x(39.09)/(0.855x6.02x10^23)]=1.5189x10^-22 cm^3
but as the cell volume is
a^3 =v
cm
for a BCC structure, the atomic radius is equal to