You regroup because the 4 in 64 plus the 3 in 43 equals 7, then you move onto the tens place, and 60 plus 40 equals 100, so that is how. Your answer is 107.
Part A:
6 2/3 *3 1/2 = 4 1/4 * x
Part B:
20/3 * 7/2 = 17/4 *x
x=20/3 * 7/2 * 4/17
x=(20*7*4) / (3*2*17)
x=560 / 102
<span>x= 5 25/51</span>
Answer:
44?
Step-by-step explanation:
I realy just have a feeling
Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
110 minus 52 is 58 so the answer would be 58 more pitches
