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stealth61 [152]
3 years ago
13

There are several reagents that can be used to effect addition to a double bond including: acid and water, oxymercuration–demerc

uration reagents, and hydroboration–oxidation reagents. Select all the reasons why hydroboration–oxidation reagents were chosen to effect the following transformation instead of the other reagents?
a. The reaction requires the Markovnikov product without sigmatropic rearrangement.
b. Addition with acid and water as reagents avoids sigmatropic rearrangements.
c. Hydroboration-oxidation reagents yield the anti-Markovnikov product of addition.
d. The reaction requires anti-Markovnikov product without sigmatropic rearrangement.
e. Addition with acid and water as reagents gives the Markovnikov product.
f. Hydroboration-oxidation reagents yield the Markovnikov product of addition.
g. The reaction requires sigmatropic rearrangement.

Chemistry
2 answers:
ExtremeBDS [4]3 years ago
7 0

The answer & explanation for this question is given in the attachment below.

Free_Kalibri [48]3 years ago
3 0

Answer:

The reaction requires anti-Markovnikov product without sigmatropic rearrangement.

Explanation:

The reaction is known to begin with the concerted syn addition of B and H across the double bond, with the boron adding to the less substituted carbon atom.

The second step of the reaction involves hydrogen peroxide and a base such as NaOH are added, NaOH deprotonates the hydrogen peroxide.

The resulting NaOOH then attacks the boron and sets up the key migration step, where the carbon-boron bond migrates to the oxygen bound to boron, breaking the weak oxygen-oxygen bond . Then the -OH expelled then returns to form a bond on the boron resulting in a deprotonated alcohol (alkoxide). The alkoxide is then protonated by water or some other comparably acidic species.

Hydroboration is a syn addition that gives an anti-Markovnikov product without sigmatropic rearrangement.

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Aqueous potassium phosphate was mixed with aqueous magnesium chloride, and a crystallized magnesium phosphate product was formed
scoray [572]

<u>Answer:</u> The other product formed is potassium chloride.

<u>Explanation:</u>

Precipitation reaction is defined as the chemical reaction in which an insoluble salt is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

The chemical equation for the reaction of potassium phosphate and magnesium chloride follows:

2K_3PO_4(aq.)+3MgCl_2(aq.)\rightarrow Mg_3(PO_4)_2(s)+6KCl(aq.)

By Stoichiometry of the reaction:

2 moles of aqueous solution of potassium phosphate reacts with 3 moles of aqueous solution of magnesium chloride to produce 1 mole of solid magnesium phosphate and 6 moles of aqueous solution of potassium chloride.

Hence, the other product formed is potassium chloride.

4 0
4 years ago
A saturated solution __________. (A) contains as much solvent as it can hold(B) contains no double bonds(C) contains dissolved s
damaskus [11]

Answer:contains as much solvent as it can hold

Explanation:

A saturated solution is a solution that contains just as much solute as it can normally hold at a particular temperature. A saturated solution has just the right amount of solute dissolved in it to give a clear solution. More solute will not dissolve after saturation.

8 0
4 years ago
* GIVING BRAINLIEST*
sveticcg [70]

i think its double replacement if i'm not mistaken  

6 0
3 years ago
A 2.00 L sample of gas at 35C is to be heated at constant pressure until it reaches a volume of 5.25 L. To what Kelvin temperatu
Anastaziya [24]

Answer:

The sample will be heated to 808.5 Kelvin

Explanation:

Step 1: Data given

Volume before heating = 2.00L

Temperature before heating = 35.0°C = 308 K

Volume after heating = 5.25 L

Pressure is constant

Step 2: Calculate temperature

V1 / T1 = V2 /T2

⇒ V1 = the initial volume = 2.00 L

⇒ T1 = the initial temperature = 308 K

⇒ V2 = the final volume = 5.25 L

⇒ T2 = The final temperature = TO BE DETERMINED

2.00L / 308.0 = 5.25L / T2

T2 = 5.25/(2.00/308.0)

T2 = 808.5 K

The sample will be heated to 808.5 Kelvin

7 0
4 years ago
People often think bonds store or hold energy. If that is true, should the energy be high or low when a bond forms?
marta [7]

Answer:

The energy should be high.

Explanation:

Bonds do store energy and release it depending if it's endothermic or exothermic. The energy should be low because when a bond forms (endothermic) it releases heat, which helps form bonds. Having a high energy means the bond is absorbing energy, which helps break bonds (endothermic). How this helps!

4 0
3 years ago
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