Answer:
The concentrations change to maintain the original value of K.
Explanation:
The concentration changes to maintain the original value of K when the concentration of the system changes.
This is the effect concentration has on a reaction at equilibrium.
Le Chatelier's principle proposes that "if any conditions of a system in equilibrium is changed, the system will adjust itself in order to annul the effect of the change".
- The equilibrium constant K is temperature dependent.
- An increase in concentration of a specie favors the direction that uses it up and vice versa.
- This does not change the value of the equilibrium constant.
The theoretical yield of HCl produced is 56.06 grams of HCl
<u><em>calculation</em></u>
BCl₃(g) +3 H₂O(l) → H₃BO₃(s) + 3 HCl(g)
Step 1: find the moles of each reactant
moles = mass÷molar mass
moles of BCl₃ = 60.0 g÷117.16 g/mol =0.512 moles
moles of H2O = 37.5 g ÷18 g/ mol = 2.083 moles
Step 2: use the moles ratio to determine the limiting reagent
from the equation above BCl₃ :HCl is 1:3 therefore the moles of HCl = 0.512 moles x 3/1 =1.536 moles
H2O :HCl is 3:3 = 1:1 therefore the moles of HCl is also 2.083 moles
Bcl₃ is the limiting reagent since it produces less amount of HCl therefore the moles HCl is 1.536 moles
Step 3 ; find the theoretical yield
The theoretical yield = moles x molar mass
from periodic table the molar mass of HCl = 1+ 35.5= 36.5 g/mol
Theoretical yield= 1.536 moles x 36.5 g/mol =56.06 g of Hcl
Answer:
Ka = 1.14x10⁻⁸
Explanation:
First we <u>calculate [H⁺] from the pH</u>:
- [H⁺] =
For a monoprotic weak acid, the molar concentration of H⁺ of a solution can be expressed as:
Where C is the molar concentration of the weak acid solution.
- 6.31x10⁻⁵ M =
Answer:
D
Explanation:
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Answer:
156 Hydrogen atoms
Explanation:
<u>Any acyclic alkane has a molecular formula that can be expressed as</u>:
CₙH₂ₙ₊₂
Where <em>n</em> is any integer and the number of carbon atoms. For example, Propane has 3 carbon atoms, this means it would have [2*3+2] 8 hydrogen atoms, resulting with a formula of C₃H₈.
An acyclic alkane with 77 carbon atoms would thus have:
2*77 + 2 = 156 hydrogen atoms