Bohr’s theory was inadequate because it did not explain the energies absorbed and released by atoms with more than one electron. It worked well for hydrogen atoms but did not work when applied to more complex atoms.
Explanation:
The given data is as follows.
Mass of a lead atom = 
Volume = 2.00 
Density = 11.3 
As it is mentioned that 1 cubic centimeter contains 11.3 grams of lead.
So, in 2 cubic centimeter there will be
of lead atoms.
One lead atom has a mass of
. Therefore, number of atoms present in 22.6 g of lead will be as follows.

= 
Thus, we can conclude that there are
of lead are present.
Answer is: -963,8 kJ.
Q₁ = m(Fe) · C · ΔT₁.
C - specific heat capacity of liquid iron, C(Fe) = 0,82 J/g°<span>C.
</span>m(Fe) = 575 g.
ΔT₁ = 1181 - 1825 = -644°C.
Q₁ = -859306,5 J = -859,3 kJ.
Q₂ = m(Fe) · C · ΔT₂.
ΔT₂ = 293 - 1181 = -888°C.
C - specific heat capacity, C(Fe) = 0,44 J/g°C.
Q₂ = -224664 J = -224,66 kJ.
Q₃ =- heat of fusion, ΔH = 209 J/g.
Q₃ = 120175 J = 120,17 kJ.
Q = Q₁ + Q₂ + Q₃ = -963,8 kJ.
Answer:
Order of increasing strength of intermolecular attraction:
>
>
> Ar
Explanation:
can form hydrogen bond as H atom is attached with electronegative atom O.
Rest three,
,
, Ar are non-polar molecules.
In non-polar molecules, van der Waal's intermolecular forces of attractions exist. Hydrogen bonding is stronger intermolecular attraction then van der Waal's intermolecular forces of attraction, hence,
has strongest intermolecular attractions.
Ar will have least intermolecular attraction, as it behaves almost as ideal gas and there is no intermolecular attraction exist between molecules of ideal gases.
Molecular size and mass of
is high as compared to
.
van der Waals intermolecular forces of attraction increases with increase in size.
Therefore,
Order of increasing strength of intermolecular attraction will be:
>
>
> Ar
Majority of an atoms mass comes for protons and neutrons which makes up the nucleus.