Answer:
yes....
Explanation:
Let me explain the molecular orbital diagram of N2 using its diagram.
one atom of nitrogen has 7 electrons so a N2 molecule will have 14 electrons
so first 2 electrons go in 1s sigma bond
next 2 in 1s sigma anti bond orbital
next 2 in 2s sigma bond orbital
next 2 in 2s sigma anti bond orbital
next 2 in 2pz sigma bond( assuming that z axis is the internuclear axis ) orbital
Taking into account the definition of density, the density of the sample is 0.5 .
It is necessary yo know that density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density allows you to measure the amount of mass in a certain volume of a substance.
Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
In this case, you know:
Then, replacing in the definition of density:
Solving:
<u><em>density= 0.5 </em></u><u><em /></u>
Finally, the density of the sample is 0.5 .
Learn more about density:
Answer:
ΔrxnHº =-1,124.3 kJ
Explanation:
To solve this question we first need to search for the enthalpies of formation of reactants and products and calculate the change in enthalpy of reaction utilizing the equation
ΔrxnHº = ∑ νΔfHº reactants - Σ νΔfHº products
where ν is the stoichiometric coefficient of the compound in the balanced equation .
ΔfHº H₂S(g) = -20.50 kJmol⁻¹
ΔfHº 0₂(g) = 0 ( O₂ is in standard state )
ΔfHº H₂O(l) = -285.8 kJmol⁻¹
ΔfHº SO₂(g) = -296.84 kJmol⁻¹
ΔrxnHº = [2 x -285.8 + 2 x -296.84] - [2 x -20.50]
= - 1,124.3 kJ
Answer:
6 moles of SO₃ formed.
Explanation:
Given data:
Number of moles of SO₃ formed = ?
Number of moles of oxygen react = 3 mol
Solution:
Chemical equation;
2SO₂+ O₂ → 2SO₃
now we will compare the moles of oxygen and sulfur trioxide.
O₂ : SO₃
1 : 2
3 : 2/1×3 = 6 moles
Thus, six moles of SO₃ will formed.