Question

A mixture of gases with a pressure of 800 mmhg contains 10% oxygen and 90% nitrogen by volume. what is the partial pressure of the oxygen gas in the mixture?[

Answer 1

    The  partial     pressure  of  the  oxygen  gas  in  the  mixture  is  calculated  is  calculated  as  follows


total  pressure  of oxygen  +    nitrogen  
the  partial pressure   of  oxygen    percentage  of  0xygen  /  total  percentage x   total  pressure
  =  10/100x800=  80  mmHg

Answer 2

Answer:

The partial pressure of the oxygen gas in the mixture is 80 mmHg.

Explanation:

Total pressure of the gas mixture ,p = 800 mmHg

Percentage of oxygen gas = 10% = 0.10 =$\chi_{O_2}$

Percentage of nitrogen gas = 90% = 0.90=$\chi_{N_2}$

Partial pressure an individual gas in a mixture is given by Dalton's law of partial pressure:

$p_{O_2}=p\times \chi_{O_2}=800 Hg \times 0.10 =80 mmHg$

$p_{N_2}=p\times \chi_{O_2}=800 Hg \times 0.90 =720 mmHg$

The partial pressure of the oxygen gas in the mixture is 80 mmHg.