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3 years ago

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A mixture of gases with a pressure of 800 mmhg contains 10% oxygen and 90% nitrogen by volume. what is the partial pressure of t

he oxygen gas in the mixture?[

2 answers:

vladimir2022 [97]3 years ago

7 0

The partial pressure of the oxygen gas in the mixture is calculated is calculated as follows

total pressure of oxygen + nitrogen
the partial pressure of oxygen percentage of 0xygen / total percentage x total pressure
= 10/100x800= 80 mmHg

stiv31 [10]3 years ago

7 0

Answer:

The partial pressure of the oxygen gas in the mixture is 80 mmHg.

Explanation:

Total pressure of the gas mixture ,p = 800 mmHg

Percentage of oxygen gas = 10% = 0.10 = $\chi_{O_2}$

Percentage of nitrogen gas = 90% = 0.90= $\chi_{N_2}$

Partial pressure an individual gas in a mixture is given by Dalton's law of partial pressure:

$p_{O_2}=p\times \chi_{O_2}=800 Hg \times 0.10 =80 mmHg$

$p_{N_2}=p\times \chi_{O_2}=800 Hg \times 0.90 =720 mmHg$

The partial pressure of the oxygen gas in the mixture is 80 mmHg.

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