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juin [17]
4 years ago
6

Given the following reaction: 3D(g) + E(g) + 2F(g) → 5G(g) + 4H(g)

Chemistry
1 answer:
evablogger [386]4 years ago
4 0

Answer:

Explanation:

Hello,

The law of mass action, allows us to know the required amounts, thus, for this chemical reaction it is:

\frac{1}{-3} \frac{d[D]}{dt} =\frac{1}{-1} \frac{d[E]}{dt} =\frac{1}{-2} \frac{d[F]}{dt} =\frac{1}{5} \frac{d[G]}{dt} =\frac{1}{4} \frac{d[H]}{dt}

Now, we answer:

(a)

\frac{d[H]}{dt}=4*\frac{1}{-3} *(-0.12M/s)=0.16M/s

(b)

\frac{d[E]}{dt}=-1*\frac{1}{5} *(0.2M/s)=-0.04M/s

(c) Since no initial data is specified, we could establish the rate of the reaction as based of the law of mass action:

r=\frac{1}{-3} \frac{d[D]}{dt} =\frac{1}{-1} \frac{d[E]}{dt} =\frac{1}{-2} \frac{d[F]}{dt} =\frac{1}{5} \frac{d[G]}{dt} =\frac{1}{4} \frac{d[H]}{dt}

Thus, any of the available expressions are suitable to quantify the rate of the reaction.

Best regards.

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