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Kisachek [45]
3 years ago
9

A general chemistry student found a chunk of metal in the basement of a friend's house. To figure out what it was, she tried the

following experiment. First she measured the mass of the metal to be 385.8 grams. Then she dropped the metal into a measuring cup and found that it displaced 17.8 mL of water. Calculate the density of the metal. Density = _______ g/mL Use the table below to decide the identity of the metal. This metal is most likely _________.
substances density g/cm3
water 1.00
aluminium 2.72
chromium 7.25
nickel 8.91
silver 10.50
lead 11.34
Chemistry
2 answers:
mr_godi [17]3 years ago
6 0

Answer:

do you have options for this

Kobotan [32]3 years ago
4 0

1. 21.67g/ml

2. aluminium

Explanation:

1. density = mass/volume

385.8/17.8= 21.67ml

2. 1g/ml=0.1g/cm^3

21.67g/ml = 2.167g/cm^3

..... substance is probably aluminium

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You are on an alien planet where the names for substances and the units of measures are very unfamiliar. Nonetheless, you obtain
Margarita [4]

Answer: 12


Explanation.


This problem was recently posted and deals with the conversion of units,so I give the same answer.


You need to convert the 9 quibs of skvarnick to sleps, to determine how many sleps you have.


The conversion of units is easily undertaken once you build your conversion factors.


Conversion factors are ratios (fractions) equivalent to one, which permits use the identity property of the multiplication to change one unit to a different equivalent one.


Remember that the identity property of multiplication states that any amount multiplied by 1 remains unchanged, i.e.

               a.1=a

Then, build your conversion factor from the definitions given:

  •    12 sleps is equal to 9 quibs.
  •    12 sleps = 9 quibs
  •    in virtue of the division property of equality, you can divide both sides by 12 sleps and get:

                                       1 = 12 sleps /  9 quibs ← conversion factor

Now you can multiply the amount 9 quibs by the conversion factor, which is equal to 1, to find the equivalent amount of sleps:


  •    identity property: 9 quibs = 9 quibs × 1
  •    substitution property: 9 quibs = 9 quibs ×  12 sleps/  9 quibs

You can see that the unit quibs appear in the numerator and the denominator so it cancels out, and the result will be in sleps.


So, all you have to do now is the operations with the numbers:

       9 quibs = (9 ×  12 / 9) sleps = 12 sleps ← answer

3 0
3 years ago
A fixed mass of oxygen gas occupies 300cm cube at 0 degree centigrade. what volume would the gas occupy at 15 degree centigrade​
egoroff_w [7]

Answer:

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to 316.5 centimeter cube

Explanation:

Assuming Pressure is constant.

\frac{V_1}{T_1} = \frac{V_2}{T_2}

where T1 and T2 are temperature in Kelvin

Substituting the give values we get-

\frac{300}{273} = \frac{V_2}{288}

V_2 = \frac{288*300}{273} \\V_2 = 316.5

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to 316.5 centimeter cube

5 0
2 years ago
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