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timofeeve [1]
3 years ago
9

Why is an alloy is often more useful than a pure metal

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
4 0
<h2>Answer:</h2>

A pure metal has specific properties. Sometimes we need that metal but with modified properties. So for the modification of properties we make alloys.

<h3>Explanation;</h3>
  • An alloy is a mixture of two elements, one of which is a metal.
  • Alloys often have properties that are different to the metals they contain.
  • This makes them more useful than the pure metals alone.
  • For example, alloys are often harder than the metal they contain.
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Freon-12, CF2Cl2, which has been widely used in air conditioning systems, is considered a threat to the ozone layer in the strat
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Answer:

The root mean squared velocity for CF2Cl2 is  v_{rms}= 207.06 m/s

Explanation:

From the question we are told that

         The temperature is T = -65 ^oC = -65+273 = 208K

Root Mean Square velocity is mathematically represented as

      v _{rms} = \sqrt{\frac{3RT}{MW} }

 Where  T is the temperature

              MW is the molecular weight of gas

              R is the gas constant with a value of  R = 8.314 JK^{-1} mol^{-1}

For  CF2Cl2 its molecular weight is  0.121 kg/mol

     Substituting values

  v_{rms} = \sqrt{\frac{3 * 8.314 *208}{0.121} }

          v_{rms}= 207.06 m/s

5 0
3 years ago
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What is pyruvate converted to
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Answer:

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Explanation:

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Fossil fuels became an important energy source during the
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mid-1700s during the Industrial Revolution

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A solution of 100.0 mL of 0.200 M KOH is mixed with a solution of 200.0 mL of 0.150 M NiSO4. (a) Write the balanced chemical equ
NISA [10]

Answer:

a) 2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂

b) Ni(OH)₂

c) KOH

d) 0.927 g

e) K⁺=0.067 M, SO₄²⁻=0.1 M, Ni²⁺=0.067 M

Explanation:

a) The equation is:

2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂   (1)        

b) The precipitate formed is Ni(OH)₂  

 

c) The limiting reactant is:

n_{KOH} = V*M = 100.0 \cdot 10^{-3} L*0.200 mol/L = 0.020 moles

n_{NiSO_{4}} = V*M = 200.0 \cdot 10^{-3} L*0.150 mol/L = 0.030 moles

From equation (1) we have that 2 moles of KOH react with 1 mol of NiSO₄, so the number of moles of KOH is:

n = \frac{2}{1}*0.030 moles = 0.060 moles                  

Hence, the limiting reactant is KOH.  

d) The mass of the precipitate formed is:

n_{Ni(OH)_{2}} = \frac{1}{2}*n_{KOH} = \frac{1}{2}*0.020 moles = 0.010 moles

m = n*M = 0.010 moles*92.72 g/mol = 0.927 g  

e) The concentration of the SO₄²⁻, K⁺, and Ni²⁺ ions are:

C_{K^{+}} = \frac{2*\frac{1}{2}*n_{KOH}}{V} = \frac{0.020 moles}{0.300 L} = 0.067 M  

C_{SO_{4}^{2-}} = \frac{\frac{1}{2}*n_{KOH + (0.03 - 0.01)}}{V} = \frac{0.030 moles}{0.300 L} = 0.1 M

C_{Ni^{2+}} = \frac{0.020 moles}{0.300 L} = 0.067 M

I hope it helps you!                                                                        

5 0
4 years ago
The reaction of 2,2-dimethyl-1-piopanol with HBr is very slow and gives 2-bromo- 2-methyIbutane as the major product. Give a mec
Elza [17]

Answer:

Correct option : "The mechanism results in a carbocation rearrangement in which a methyl shift occurs"

Explanation:

In the first step, 2,2-dimethyl-1-propanol gets protonated.

In the second step, a carbocationic intermediate is produced from removal of H_{2}O.

In the third step, shifting of methyl group occurs to produce more stable carbocationic intermediate.

In the fourth step, Br^{-} attacks the stable carbocation to produce 2-bromo-2-methylbutane.

So, correct option : "The mechanism results in a carbocation rearrangement in which a methyl shift occurs"

Full reaction mechanism has been shown below.

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