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MissTica
3 years ago
15

How does mass affect a star's life cycle?

Chemistry
1 answer:
Andre45 [30]3 years ago
3 0

Answer:

<h2>A star's life cycle is determined by its mass. The larger its mass, the shorter its life cycle. A star's mass is determined by the amount of matter that is available in its nebula, the giant cloud of gas and dust from which it was born. ... As the gas spins faster, it heats up and becomes as a protostar.</h2>

Explanation:

<h2>Read this and then choose your options ✍️✍️</h2>
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Which of the following is NOT true regarding Rutherford's Gold Foil experiment?
erastova [34]

Answer:

The area around the nucleus must be of low mass.

Explanation:

Rutherford`s experiment showed that there are some positive charges in the center of the atoms, and because they are all together, they will give a great mass to the atom.

It was quite different from Thomson`s experiment, in which it was thought that the negative charges were mixed with the positive charges, around the atom (like a Pudding Model). In Rutherford`s experiment, because the direction of beta particles, it was the prediction of the positive nucleus.

Hope this info is useful.

8 0
3 years ago
Help PlS AFAP and thank you so much
Triss [41]

Answer:

B

Explanation:

idk how to explain, B is the definition of conduction

8 0
3 years ago
Read 2 more answers
Please Which one??? is it???
Tatiana [17]
The 1st one. Fertilizers are like food for plants, and that's what an algae is, sorta. Trout's don't eat algae and if there's too much algae around, it gets dirty and they eventually die because of the amount of bacteria in the algae. It's the same thing if you have a fish tank.
6 0
3 years ago
Read 2 more answers
How much work (in JJ) is required to expand the volume of a pump from 0.0 LL to 2.5 LL against an external pressure of 1.1 atmat
stira [4]

Answer:

- 278.85 J  

Explanation:

Given that:

Pressure = 1.1 atm

The initial volume V₁ = 0.0 L

The final volume V₂ = 2.5 L

The work that takes place in a reaction at constant pressure can be expressed by using the equation:

W = P(V₂ - V₁ )

Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:

W = - P(V₂ - V₁ )

W = -1.1 atm ( 2.5 - 0.0) L

W = -1.1 atm (2.5 L)

W = -2.75 atm L

Recall that:

1 atm L = 101.4 J

Therefore;

-2.75 atm L = ( -2.75 × 101.4 )J

= -278.85 J  

Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm  = - 278.85 J  

8 0
3 years ago
PLEASE HELP:
klio [65]

Answer:

Oil spills

Explanation:

I've done it before

5 0
3 years ago
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