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2 years ago

Carbon dioxide is released into the atmosphere by _____.

Chemistry

1 answer:

kirill115 [55]2 years ago

3 0

Answer:

4 a minor but very important component of the atmosphere corban dioxide is released through natural processes such as reputation.;

Explanation:

a minor but very important component of the atmosphere corban dioxide is released through natural processes such as reputation

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In the compound sodium methoxide (naoch3), there is ________ bonding

zvonat [6]

Maybe covalent bonding?

5 0

2 years ago

g Consider a uniport system where a carrier protein transports an uncharged substance A across a cell membrane. Suppose that at

Alborosie

Answer : The ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

$\Delta G^o=-RT\times \ln Q\\\\\Delta G^o=-RT\times \ln (\frac{[A]_{inside}}{[A]_{outside}})$

where,

$\Delta G^o$ = standard Gibbs free energy = -14.1 kJ/mol

R = gas constant = 8.314 J/K.mol

T = temperature = $25^oC=273+25=298K$

Q = reaction quotient

$[A]_{inside}$ = concentration inside the cell

$[A]_{outside}$ = concentration outside the cell

Now put all the given values in the above formula, we get:

$-14.1\times 10^3J/mol =-(8.314J/K.mol)\times (298K)\times \ln (\frac{[A]_{inside}}{[A]_{outside}})$

$\frac{[A]_{inside}}{[A]_{outside}}=296.2$

Thus, the ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2

3 0

2 years ago

Analyzing and interpreting data

Lana71 [14]

It’s blurry i can’t see

4 0

2 years ago

1. At STP, you have 0.101 g of carbon dioxide gas. What is the volume of this gas?

Ber [7]

Answer:

1) A. 0.0515 L

2) B. 35.504 L

3) B. 422.446 g

Explanation:

At STP, you have 0.101 g of carbon dioxide gas. What is the volume of this gas?

Step 1: Data given

Mass of CO2 gas = 0.101 grams

Molar mass of CO2 = 44.01 g/mol

STP = 1 atm and 273K

Step 2: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 0.101 grams / 44.01 g/mol

Moles CO2 = 0.0023 moles

Step 3: Calculate the volume

For 1 mol at STP we have 22.4L

0.0023 moles we have 22.4L * 0.0023 = 0.0515 L

Option A is correct

You have 27g of ammonia (nitrogen trihydride) at STP. What is the volume? Hint...you will first need to convert mass of ammonia to moles!

Step 1: Data given

Molar mass of NH3 = 17.03 g/mol

Mass of NH3 = 27.00 grams

STP = 1 atm and 273K

Step 2: Calculate moles NH3

Moles NH3 = 27.00 grams / 17.02 g/mol

Moles NH3 = 1.585 moles

Step 3: Calculate volume

For 1 mol at STP we have 22.4 L

For 1.585 moles we have 22.4 * 1.585 = 35.504 L

Option B is correct

Which of the following represents the MASS of 215 L of dinitrogen monoxide at STP? Hint...find the # of moles of this gas and then use the molar mass to go from moles to mass!

Step 1: Data given

Volume = 215 L

STP = 1 atm and 273 K

Molar mass of N2O = 44.01 g/mol

Step 2: Calulate moles N2O

22.4L = 1 mol at STP

215 L = 215 / 22.4 = 9.60 moles

Step 3: Calculate mass N2O

Mass N2O = moles N2O * molar mass N2O

Mass N2O = 9.60 moles* 44.01 g/mol

Mass N2O = 422.446 g

Option B is correct

3 0

2 years ago

Find the force it would take to accelerate an 800-kg car at a rate of 5m/s2.

laila [671]

Force= mass•acceleration

Force=800•5

Force=4000 N

3 0

2 years ago

Read 2 more answers