The domain in a relation y(x) is the set of values for which the relation is defined (the values on x, where y is defined)
In this relation the values wich the relation is defined is: the coordinates of x where there are a point:
Domain: -1, 0, 3
The range in a relation y(x) is the set of all the values that y(x) takes (the values of y)
In this relation the values that takes y(x) are the coordinates of y where there are a point:
Range: -3, -1, 0
Answer:
50 Notebooks
Step-By-Step:
First write an equation
3/5x
The x represent the number of notebooks that can fit within the shelf.
So 3/5(50)=30
Answer:
7/11
Step-by-step explanation:
This is the only fraction without a 1 in its numerator.
Answer:
v_top = 2400 mi/hr
v_w = 400 mi/h
Step-by-step explanation:
Given:
- Total distance D = 4800 mi
- Headwind journey time taken t_up= 3 hr
- Tailwind journey time taken t_down = 2 hr
Find:
Find the top speed of Luke's snow speeder and the speed of the wind.
Solution:
- The speed of Luke v_l is in stationary frame is given by:
v_l = v_w + v_l/w
Where,
v_w: Wind speed
v_l/w: Luke speed relative to wind.
- The top speed is attained on his returned journey with tail wind. We will use distance time relationship to calculate as follows:
v_top = D / t_down
v_top = 4800 / 2
v_top = v_down = 2400 mi/hr
- Similarly his speed on his journey up with head wind was v_up:
v_up = D / t_up
v_up = 4800 / 3
v_up = 1600 mi/hr
- Now use the frame relations to find the wind speed v_w:
v_down = v_w + v_l/w
v_up = -v_w + v_l/w
- Solve equations simultaneously:
2400 = v_w + v_l/w
1600 = -v_w + v_l/w
4000 = 2*v_l/w
v_l/w = 2000 mi/h
v_w = 400 mi/h
