∠13 = 70.5° [Vertically Opposite angles]
∠13+∠14=180° [Linear pair]
70.5°+∠14=180°
∠14=180-70.5
∠14=109.5
∠15=∠14=109.5 [Vertically opposite angles]
∠13=∠12= 70.5° [Co-interior angles]
∠12=∠10= 70.5° [Vertically Opposite angles]
∠14=∠11=109.5 [Co-interior angles]
∠9=∠11= 109.5 [Vertically opposite angles]
∠13=∠7= 70.5° [Alternate interior angles]
∠7=∠5=70.5° [Vertically Opposite angles]
∠7+∠8=180° [Linear Pair]
70.5+∠8=180
∠8=180-70.5
∠8=109.5°
∠8=∠6= 109.5° [Vertically Opposite angles]
∠6=∠3=109.5° [Co-interior angles]
∠7=∠2=70.5° [Co-exterior angles]
∠2=∠4= 70.5° [Vertically Opposite angles]
∠3=∠1= 109.5° [Vertically Opposite angles]

<h3>Measures of all angles in sequence⤵️</h3>
- ∠1= 109.5°
- ∠2= 70.5°
- ∠3= 109.5°
- ∠4= 70.5°
- ∠5= 70.5°
- ∠6= 109.5°
- ∠7= 70.5°
- ∠8= 109.5°
- ∠9= 109.5°
- ∠10= 109.5°
- ∠11= 70.5°
- ∠12= 109.5°
- ∠13= 70.5°
- ∠14= 109.5°
- ∠15= 109.5°
- ∠16= 70.5°
Answer:
16
Step-by-step explanation:
30-10=20
20 divided by 1.25 = 16
Hello from MrBillDoesMath!
Answer:
x = 0, 7
Discussion:
f(g(x)) =
f ( x^2-7x) =
1/ ( x^2 - 7x)
The points NOT in the domain are those where the denominator, x^2 - 7x = 0.
x^2 - 7x = 0 => factor x from each term
x(x-7) = 0 => one or both terms must each 0
x = 0 or x =7
Thank you,
MrB
Given:
is subtracted from 3.
To find:
The result of the given statement in the standard form of the polynomial.
Solution:
We need to find the result when
is subtracted from 3.
So, the resulted polynomial can be written as:

On simplification, we get
![[\because (a+b)^2=a^2+2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a%2Bb%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%5D)
Therefore, the resulted polynomial in standard form is
.