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Marianna [84]
3 years ago
13

Explain why sublimation and deposition are classified as physical changes

Physics
1 answer:
Over [174]3 years ago
7 0
Because even though it goes through a phase change it's still water
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Two sound waves, from two different sources with the same frequency of 420 Hz travel in the same direction at 336 m/s. The sourc
Tresset [83]

Answer:

Pi(3.14) radians or 180º degrees

Explanation:

First of all, we need to obtain the wavelength of a wave traveling to the speed of sound and 420 Hz of frequency.

The formula is:

l=wavevelocity/frequency

where l = wavelength in meters

With current values:

l = 336 [m/s]/420[1/s] = 0.8 meters

Since a complete cycle (360º or 2pi radians) needs 0.8 meters to complete, 0.4 meters or 40 cm is just half of it, making a 180º degree phase or 3.14 radians.

8 0
3 years ago
What kind of water that most used in industrial
ValentinkaMS [17]

<em>Hard </em><em>water </em><em>is </em><em>mostly </em><em>used </em><em>in </em><em>Industries </em>

3 0
3 years ago
8. The pulley is assumed massless and frictionless and rotates freely about its axle. The blocks have masses m = 40 g and m₂ = 2
gayaneshka [121]

The magnitude of the acceleration of block m2  is 0.09 m/s² and the tension in the cord is 1.8 x 10⁻³ N.

<h3>Acceleration of the blocks</h3>

The acceleration of the blocks is calculated from the net force on the blocks.

∑F = ma

a = ∑F/m

a = (F) / (m₁ + m₂)

where;

  • F is the horizontal force applied
  • m₁ is mass of first block = 40 g = 0.04 kg
  • m₂ is mass of the second block = 20 g = 0.02 kg

a = (0.03)/(0.04 + 0.02)

a = 0.09 m/s²

<h3>Tension due to block m₂</h3>

T = m₂a

T = (0.02 x 0.09) = 1.8 x 10⁻³ N

Thus, the magnitude of the acceleration of block m2  is 0.09 m/s² and the tension in the cord is 1.8 x 10⁻³ N.

Learn more about tension here: brainly.com/question/24994188

#SPJ1

3 0
2 years ago
If the pitch of a sound decreases and the sound source is moving, is the sound source moving toward or away from the observer
fiasKO [112]
The sound source must be moving away
6 0
3 years ago
A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1.1 ft/s,
IRINA_888 [86]

Explanation:

If the distance between the bottom of the ladder and the wall is x, then:

cos θ = x / 10

Taking derivative with respect to time:

-sin θ dθ/dt = 1/10 dx/dt

Substituting for θ:

-sin (acos(x / 10)) dθ/dt = 1/10 dx/dt

Given that x = 6 and dx/dt = 1.1:

-sin (acos(6/10)) dθ/dt = 1/10 (1.1)

-0.8 dθ/dt = 0.11

dθ/dt = -0.1375

The angle is decreasing at 0.1375 rad/s.

3 0
3 years ago
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