Answer:
so each bulb brightness becomes half of its given or indicated power
so both bulb will glow same power as indicated
Explanation:
Let the indicated power on the bulbs is given as P and its rated voltage is V
so here resistance of each bulb is given as
now if the two bulbs are connected in series so we will have
now the current in the circuit is given as
now brightness of each bulb is given as
so each bulb brightness becomes half of its given or indicated power
Now if the two bulbs are connected in parallel
then the net voltage across each bulb is "V"
so we will have
so both bulb will glow same power as indicated
Which force is always perpendicular (90 degree angle) to a surface. So, if you are sitting on the floor, what is the name of the force "the floor pushes up on you"?
Question 4 options:
normal
Answer:
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Explanation:htrhstrhhstrsstrthrssr
<span>The current from the power source will not change when the second light bulb is attached. This is because the current is kept on a single path, it will return to the power source at the same value it left the source at.</span>
Answer:
a) v = 3.116 m / s, b) μ = 1.65 10⁻²
Explanation:
a) to find the velocity of the set, let's define a system formed by the person and the sled, so that the forces during the collision are internal and the moment is conserved
initial instant. Before the crash
p₀ = M v₀
final instant. After the crash
p_f = (M + m) v
the moment is preserved
M v₀ = (M + m) v
v =
let's calculate
v =
v = 3.116 m / s
b) for this part let's use the relationship between work and kinetic energy
W = ΔK
as the body has its final kinetic energy is zero
the work of the friction forces is
W = - fr x
the negative sign is because the friction forces always oppose the movement
let's write Newton's second law
Y axis
N - W_sled -W_person = 0
N = mg + M g
N = (m + M) g
X axis
fr = ma
the friction force has the expression
fr = μ N
fr = μ g (m + M)
we substitute
- μg (m + M) x = 0- ½ (m + M) v²
μ =
let's calculate
μ =
μ = 0.0165
μ = 1.65 10⁻²