A technique in which the muscles are stretched by an outside force is called Passive Stretching
Answer:
D
Explanation:
- The rate of the Diels-Alder is orders of magnitude faster if there is an electron-withdrawing group on the dienophile. For example, replacing a hydrogen on ethene with the electron-withdrawing group CN results in about a 10^5 increase in the reaction rate.
- Other common electron withdrawing functional groups that will accelerate the Diels Alder reaction of dienophiles include aldehydes, ketones, and esters.
- In short, any functional group conjugated with the pi bond which can act as a pi acceptor will accelerate a Diels-Alder reaction with a typical diene.
- See attachment for graphical explanation.
Answer:
The advertisement feature that George can use is a coupon booklet with the local newspaper for delivery
Explanation:
George focus on promotion rather than using the other stores strategy of word-of-mouth. Different types of promotion: advertising, public relations, direct selling and sales promotions.A temporary reduction in the price, such as 50% off. Reduction amount may be a percentage that can be marked on the package.A coupon booklet is inserted into the local newspaper for delivery. Also on checkout the customer can be given a coupon based on products purchased. The consumer is automatically entered into the contest/event by purchasing the product.
Displays:-
A board on which messages are written in crayon.
Consumers get one sample for free, after their trial and then could decide whether to buy or not
Ilana is togladly hospitalized for the loss and the loss and her family of the dead were in a coma and she had to go on the plane and then to go to a hotel and to see if the girl had a child and a woman was in a car crash or something like it could have caused a lot to happen with her body that could help him get out the next morning after a long day of work and a woman was in a condition of a new yo girl in her apartment and was taken into a car in a coma at a
Answer:
1.) 11 km/s
2.) 9.03 × 10^-5 metres
Explanation:
Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.
Electron q = 1.6×10^-19 C
Electron mass = 9.11×10^-31 Kg
(a) What is the speed of the electron 1.3 ns after entering this region?
E = F/q
F = Eq
Ma = Eq
M × V/t = Eq
Substitute all the parameters into the formula
9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19
V = 7.68×10^-18 /7.0×10^-22
V = 10971.43 m/s
V = 11 Km/s approximately
(b) How far does the electron travel during the 1.3 ns interval?
The initial velocity U = 64 km/s
S = ut + 1/2at^2
S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2
S =8.32×10^-5 + 7.13×10^-6
S = 9.03 × 10^-5 metres
