Answer:
correct answer is option A (Yes, becuase acceleration depends on the rate of change of velocity and not the value of velocity itself.)
Explanation:
we know that from first equation of motion,
v=u+at
0r
............(1)
here,
v-final velocity
u-initial velocity
a-acceleration
t-time
if a body is not moving it means if its initial velocity is zero (u=0) and if after time t it moves with velocity v then its acceleration will be given as
...........(2)
From above equation it is clear that if an object is not moving, it can be accelerating because acceleration depends on rate of change of velocity and not the value of velocity itself.
This is true. I hope this helps! (:
Answer: Yes both gases would have the same entropy.
Explanation:
The formula for the change in the entropy is as follows,
Here, \Delta S is the change in the entropy, Q is the heat transfer and T is the temperature.
If the temperature of the system increases then there will be increase in the entropy as the randomness of the system increases.
In the given problem, if the both gases were initially at the same absolute temperature. Then there will be same entropy change in both gases.
Therefore, yes both gases would have the same entropy.
Answer:
3.At equilibrium, its instantaneous velocity is at maximum
Explanation:
The motion of a mass on the end of a spring is a simple harmonic motion. In a simple harmonic motion, the total mechanical energy of the system is constant, and it is sum of the elastic potential energy (U) and the kinetic energy of the mass (K):
where
k is the spring constant
x is the displacement of the spring from equilibrium
m is the mass
v is the speed
As we see from the formula, since the total energy E is constant, when the displacement (x) increases, the speed (v) increases, and viceversa. Therefore, when the mass is at its equilibrium position (which corresponds to x=0), the velocity of the mass will be maximum.
Explain how they interact with each other. I'm not a chem genius but taht would make the most sense.
Hope it helps! Comment if you have any questions and have an amazing day!