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Andrej [43]
3 years ago
15

Suppose you look at a detailed spectrum of visible light from some object. How can you decide whether it is an emission line spe

ctrum or an absorption line spectrum?
Physics
1 answer:
statuscvo [17]3 years ago
3 0

Answer:

By observing the color of lines in the spectrum.

Explanation:

There are two types of lines in the spectrum explained below:

i) Bright lines: Bright lines occurs on the spectrum when atoms emit photons. These bright lines show the emission line spectrum.

ii) Dark Lines: Dark lines occurs on the spectrum when atoms absorb photons. These black lines show the absorption line spectrum.

Hence, by observing the color of lines it is possible to identify emission line spectrum and absorption line spectrum.

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A 5kg object moving horizontally at 3m/s collides with a stationary 3kg object. After the collision, the 5kg object is deflected
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Answer:

The velocity of each ball after the collision are 2.19 m/s and 2.58 m/s.

Explanation:

Given that,

Mass of object = 5 kg

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Stationary object deflected = 31°

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m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}\cos\theta+m_{2}v_{2}\cos\theta

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15=5v_{1}\times\dfrac{\sqrt{3}}{2}+3v_{2}\times\dfrac{1}{\sqrt{2}}

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Along y -axis

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}\sin\theta+m_{2}v_{2}\sin\theta

Put the value into the formula

0+0=5\times v_{1}\sin30-3\times v_{2}\sin45

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From equation (I) and (II)

v_{1}=\dfrac{15\times2}{5\sqrt{3}+5}

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\dfrac{5}{2}\times2.19-\dfrac{3}{\sqrt{2}}v_{2}=0

v_{2}=\dfrac{5.475\times\sqrt{2}}{3}

v_{2}=2.58\ m/s

Hence, The velocity of each ball after the collision are 2.19 m/s and 2.58 m/s.

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