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Mariana [72]
3 years ago
10

Both high-side pressures and low-side pressures are low with the engine running and the selector set to the air-conditioning pos

ition. Technician A says that the system is undercharged. Technician B says the cooling fan could be inoperative. Which technician is correct?A. Technician A onlyB. Technician B onlyC. Both technicians A and BD. Neither technicians A nor B
Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

Technician A only

Explanation:

Both high-side pressures and low-side pressures are low with the engine running and the selector set to the air-conditioning position. Technician A says that the system is undercharged. Technician B says the cooling fan could be inoperative. Which technician is correct?

usually . An overcharged system will result in lower than normal low side pressures

An undercharged system will not enable  the compressor  to create pressure. As a result of the low amount of refrigerant, the cooling ability is reduced. When we say undercharged, we mean the refrigerant in the system is low, so the both the high side pressures and low side pressures will be low.

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A car travels 98 miles in 1 hour and 45 minutes. what is the average speed?
Greeley [361]
Firstly let us get the time down to minutes from hours. Then the calculation will become easy.
1 hour and 45 minutes = (60 + 45) minutes
                                     = 105 minutes
So
The distance traveled by the car in 105 minutes = 98 miles
Then
The distance traveled by the car in 60 minutes = (98/105) * 60 miles
                                                                           = 5880/105 miles
                                                                           = 56 miles
So the average speed of the car as can be seen from the above deduction is 56 miles per hour.
4 0
3 years ago
I’m totally stuck and I don’t know what to do
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7 0
3 years ago
What is the relationship between height and gravitational potential energy of water behind a dam?
Andrews [41]

Answer:

3. h^2

Explanation:

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E=\dfrac{1}{2}A\rho gh^2

where,

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3 years ago
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8 0
4 years ago
Your high-fidelity amplifier has one output for a speaker of resistance 8 Ω. How can you arrange two 8-Ω speakers, one 4-Ω speak
ANTONII [103]

Answer:

(a) 8Ω (b)  Ratio = Parra/P8 ohm = 1

Explanation:

Solution

Recall that,

An high-fidelity amplifier has one output for a speaker of resistance of = 8 Ω

Now,

(a) How can  two 8-Ω speakers be  arranged, when one =  4-Ω speaker, and one =12-Ω speaker

The Upper arm is : 8 ohm, 8 ohm

The Lower arm is : 12 ohm, 4 ohm

The Requirement is  = (16 x 16)/(16 + 16) = 8 ohm

(b) compare  your arrangement  power output of with the power output of a single 8-Ω speaker

The Ratio = Parra/P8 ohm = 1

8 0
4 years ago
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