You draw a straight line from the start point to the end point. It doesn't matter what route was actually followed for the trip.
Answer:
magnitude of the frictional torque is 0.11 Nm
Explanation:
Moment of inertia I = 0.33 kg⋅m2
Initial angular velocity w° = 0.69 rev/s = 2 x 3.142 x 0.69 = 4.34 rad/s
Final angular velocity w = 0 (since it stops)
Time t = 13 secs
Using w = w° + §t
Where § is angular acceleration
O = 4.34 + 13§
§ = -4.34/13 = -0.33 rad/s2
The negative sign implies it's a negative acceleration.
Frictional torque that brought it to rest must be equal to the original torque.
Torqu = I x §
T = 0.33 x 0.33 = 0.11 Nm
Answer:
The answer to your question is C
Explanation:
acceleration is a vector quantity because it has both magnitude and direction
According to Newton`s law. Force exerted by car,
After adding an additional 400 kg of mass, the force will be same therefore the acceleration
Thus, the acceleration after adding the masses is 1.47 \ m/s^2.
