Question

Find an equation of the line passing through the point (2, -1) and the point of intersection of the lines x + 2y = 3 and 2x - 3y = 13.

Answer 1

Answer:

y=-1 is the equation of the line

Step-by-step explanation:

x + 2y = 3 and

solve for x  and y to get intersection point

multiply first equation by -2

$-2x -4y = -6$

$2x - 3y = 13$

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$-7y=7$

y=-1

$x + 2y = 3$

$x + 2(-1)= 3$

$x -2= 3$

x=5

intersection point is (5,-1)

(2, -1) and (5,-1)

$slope = \frac{y_2-y_1}{x_2-x_1} =\frac{-1+1}{5-2} =0$

Slope = 0 (horizontal line)

So equation becomes y =y1 value

y=-1 is the equation of the line