<span>(5,-1)
The key to this problem is ignoring all the information that you don't need. You really don't care about the coordinates for T, U, or V. Just W is all that matters. So make a graph, label the X and Y axis, and put a point at (1,5). Now simply turn the entire paper clockwise 90 degrees. If you do this, you'll see that what was the X axis is now the Y axis. And what was the Y axis is now the X axis. Label the axis again, and read the location of the point you marked. If you do so, you'll see that you have to go 5 spaces along the X axis, hence the 5. And you'll go 1 space down on the Y axis, hence the -1.
So the coordinates of W(1,5) rotated 90 degrees clockwise around (0,0) changes to (5,-1).</span>
Answer:
33 yrs old
Step-by-step explanation:count up to the year he was born
Answer:
2π or 0π are the only points that satisfy the expression, but since the restriction is 0 <= x < 2π
the answer would be 0π
Answer:
you just gotta look at the angles, the middle letter is usually what's being focused on
17. angle QMR is less that TMS
18. angle QMR and angle TMS are supplementary angles
19. angle QMR and angle MTS are vertical angles
20. If measure angle QMT = 70 degrees, then measure angle RMS is 70 degrees because they are congruent
Step-by-step explanation:
