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lozanna [386]
3 years ago
14

Could someone simplify?

Mathematics
1 answer:
RideAnS [48]3 years ago
8 0

Gotcha!

The answer would be -125q^6p^3

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Plutonium-240 decays according to the function Q(t) = Qoe^-kt
LuckyWell [14K]

Answer:

  9990 years

Step-by-step explanation:

The exponential function with given values filled in can be solved for the unknown using logarithms.

__

  Q(t) = 12 = 36e^(-0.00011t)

  1/3 = e^(-0.00011t) . . . . . . divide by 36

  ln(1/3) = -0.00011t . . . . . . take natural logs

  t = ln(1/3)/(-0.00011) . . . . divide by the coefficient of t

  t ≈ 9990 . . . years

5 0
2 years ago
I need help solving this problem with proofs if at all possible
k0ka [10]

I don't really like these algebra problems which pretend to be geometry.

The bisector makes two equal angles, so

x/2 + 17 = x - 33

50 = (1/2) x

x = 100

That means ABC = 100/2 + 17 = 67 degrees

CBD = 100 - 33 = 67 degrees, equal so that checks

We're asked for ABC which is 67 + 67 = 134 degrees

Answer: 134°

4 0
3 years ago
Read 2 more answers
The box plot shows the number of home runs hit by 43 players during a baseball season which stament best describes the data
ozzi

The number of data values between the lower quartile and the median is less than the number of data values between the upper quartile and the median.

Hope this helps!

6 0
3 years ago
There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl
insens350 [35]

We're told that

P(A\cap B)=0.15

P(A\cup B)^C=0.06\implies P(A\cup B)=0.94

P(B\mid A)=P(B^C\mid A)=0.5

where the last fact is due to the law of total probability:

P(A)=P(A\cap B)+P(A\cap B^C)

\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)

\implies 1=P(B\mid A)+P(B^C\mid A)

so that B\mid A and B^C\mid A are complementary.

By definition of conditional probability, we have

P(B\mid A)=P(B^C\mid A)

\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}

\implies P(A\cap B)=P(A\cap B^C)

We make use of the addition rule and complementary probabilities to rewrite this as

P(A\cap B)=P(A\cap B^C)

\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)

\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)

\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]

\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]

\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C

\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)

By the law of total probability,

P(B)=P(A\cap B)+P(A^C\cap B)

\implies P(A^C\cap B)=P(B)-P(A\cap B)

and substituting this into (*) gives

2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]

\implies P(B)=P(A\cup B)-P(A\cap B)

\implies P(B)=0.94-0.15=\boxed{0.79}

8 0
3 years ago
imagine you live only one mile from work and you decide to walk. if you walk four miles per hour, how long will it take you to w
fiasKO [112]

Answer:the distance to work is 1 mile and you can walk at 4 miles per hour, then you can walk 1 mile in ¼ hr = 15 minutes

Step-by-step explanation:

Dylan,

If the distance to work is 1 mile and you can walk at 4 miles per hour, then you can walk 1 mile in ¼ hr = 15 minutes.

To set up the "equation" think about it this way:  (1 mile/ t) = (4 mile/ 1 hr)

so 1/t = 4/1 hr  

now multiply both sides by t to get 1 = t·(4/1 hr), next divide both sides by (4/1 hr)

t = 1/(4/ 1 hr) = 1 hr/4 = ¼ hr = 15 min.

8 0
3 years ago
Read 2 more answers
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