The force on one end of the trough is 5.4 X 10⁵ N
<u>Explanation:</u>
The triangle is equilateral which means all the interior angles are 60° and the sides are 6m long.
According to the figure,
AI / 8 = sin (60) = √3/2
AI = 4√3
The depth of the water is AI = 4√3
The interval becomes, | 0 , 4√3|
w = 2JK
(the hydrostatic force acting on the strip is the product of the pressure and the area)
where.
ρ = 875 kg/m³
g = 9.8m/s²
d = depth ( d = y')
limit is 0 → 4√3
On solving the equation, we get the value of limit as 32√3
Therefore, the force on one end of the trough is 5.4 X 10⁵ N
The components are at a right angle so the resultant is R^2 = 4.50^2 + 9.80^2 R = 10.78 or 10.8
I hope this helps! :)
~erudite
Answer:
The displacement of the elevator between 8 s and 24 s is 6 m.
Explanation:
Given that,
Initial time = 8 s
Final time = 24 s
We know that,
Displacement :
Displacement is the difference between initial position and final position.
In mathematically,
We need to calculate the displacement
Using formula of displacement
Put the value from graph
Hence, The displacement of the elevator between 8 s and 24 s is 6 m.
Answer:
20.4e18 electrons/second ≈ 2e19 electrons/second
Explanation:
Hi!
To solve this problem we are going to use Omh's Law:
V = RI
And the relation ship between the resistance R and conductivity:
R = L/(σA)
*here we are considering a omhic material*
The conductance σ is related to electron mobility and electron density by:
σ = nμ
Replacing all these relations in the omhs law, we get:
V = (LI)/(σA)
We know that both wire are subject to the same electric field, therefore V is the same for both, moreover, since no additional info for the length of the wires is given we are going to consider that L is the same for both. Therefore
This means that:
From the relation of the conductance and electron mobility and density, and the data given to us, we know that:
Also
Therefore:
That is:
Since I_A = 3*10^18 e/s
I_B = 20.4*10^18 e/s
Roygbv evjnefvvnefv ekfv k kn ke nv