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3 years ago

6

Can someone help me with this math problem?

2 answers:

arlik [135]3 years ago

8 0

No, it is not a solution to the inequality.

erik [133]3 years ago

8 0

Yes you have to multiply each term by 2 so -122 is greater

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Simplify 3x + 3 + 2.<br><br> 3x + 5<br> 5x + 3<br> 8x

Pie

Answer:

<em>3x + 5</em>

Step-by-step explanation:

We are doing variables and simplifying.

You have two types of numbers here, you have a coefficient, and you have regular numbers. Now do keep in mind that you can never add a regular number to a coefficient. So the only thing in this problem you will add is 3 and 2. Because 3x is different

3x + (3 + 2)

3x + 5

6 0

3 years ago

Read 2 more answers

What has 12 edges, 12 vertices and 6 faces shaped like rectangles

aliina [53]

The answer is Cube my friend !

8 0

3 years ago

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Gerry has two different part-time jobs, and he had work 20 hours per week at each job. He earns $8 per hour at one job. Which ex

ale4655 [162]

Answer:The answer is B. 160 + 20d

Step-by-step explanation: first find out the total for how much he makes at the first job. 20 x 8 = 160 then you just write out the equation

5 0

3 years ago

PLEASE HELP, I'LL GIVE U BRAINLY

Helen [10]

Answer:

im not sure but i think its D

6 0

3 years ago

A 9.85 m ladder is placed against a wall. The height to the top of the ladder is 5 m more than the distance between the wall and

Dafna1 [17]

Given:

Length of the ladder = 9.85 m

The height to the top of the ladder is 5 m more than the distance between the wall and the foot of the ladder.

To find:

The height to the top and the distance between the wall and the foot of the ladder.

Solution:

let x be the distance between the wall and the foot of the ladder. Then the height to the top of the ladder is (x+5).

Pythagoras theorem: In a right angle triangle,

$Hypotenuse^2=Base^2+Perpendicular^2$

In the given situation, hypotenuse is the length of ladder, i.e., 9.85 m. The base is x m and the height is (x+5) m.

Using the Pythagoras theorem, we get

$(9.85)^2=x^2+(x+5)^2$

$97.0225=x^2+x^2+10x+25$

$0=2x^2+10x+25-97.0225$

$0=2x^2+10x-72.0225$

Here, $a=2, b=10,c=-72.0225$ . Using the quadratic formula, we get

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-10\pm \sqrt{(10)^2-4(2)(-72.0225)}}{2(2)}$

$x=\dfrac{-10\pm \sqrt{676.18}}{4}$

Approximating the value, we get

$x=\dfrac{-10\pm 26}{4}$

$x=\dfrac{-10+26}{4},\dfrac{-10-26}{4}$

$x=\dfrac{16}{4},\dfrac{-36}{4}$

$x=4,-9$

Distance cannot be negative so $x\neq -9.$

Now we have $x=4$

$x+5=4+5$

$x+5=9$

Therefore, the base is 4 m and the height is 9 m.

5 0

3 years ago