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nadezda [96]
4 years ago
11

The balanced equation for a hypothetical reaction is A + 5B + 6C → 3D + 3E. What is the rate law for this reaction?

Chemistry
2 answers:
Kobotan [32]4 years ago
5 0
D. <span>The rate law cannot be determined from the overall equation without experimental data.</span>
Ipatiy [6.2K]4 years ago
4 0

Answer: Rate=k[A]^1[B]^5[C]^6

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Order of the reaction is defined as the sum of the concentration of terms on which the rate of the reaction actually depends. It is the sum of the exponents of the molar concentration in the rate law expression.

Elementary reactions are defined as the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical reaction.

A+5B+6C\rightarrow 3D+3E

Rate=k[A]^1[B]^5[C]^6

k= rate constant

1 = order with respect to A

5 = order with respect to B

6 = order with respect to C

Thus rate law is Rate=k[A]^1[B]^5[C]^6

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Write the advantages of modern periodic table write as more as you can and don't copy the same thing​
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Answer:

the advantages of modern periodic tables are given below and explained.

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hope this helped you☺️

any confusion then comment it and let me know.

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3 0
3 years ago
Since children of the first union/marriage have the trait the great- grandparents do not have the trait they must have been carr
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Read 2 more answers
This question has multiple parts. Work all the parts to get the most points. An aqueous antifreeze solution is 39.0% ethylene gl
nlexa [21]

Answer:

Molality = <u>10.300 m</u>

<u>Molarity = 6.5970 M</u>

<u>mole fraction = </u>0.156549

Explanation:

39.0 % = ethylene glycol

61.0 % = water

imagine the total mass = 100g

39.0% ethylene glycol = 39g

61.0 % water = 61g

1) Molality = number of moles / mass of solvent (kg)

Molar mass of ethylene glycol = 62.07g/mole

mole = 39g / 62.07g/mole = 0.6283 moles

Molality = moles / mass of solvent = 0.6283 moles / 0.061kg = <u>10.300 m</u>

<u />

<u>2) Molarity</u> = number of moles / volume of solution

Since we know the density  of the solution = 1.05g /ml

⇒ volume = 100g / 1.05g /mL   = 95.24 mL = 0.09524 L

Molarity = 0.6283 moles / 0.09524 L = <u>6.5970 M</u>

3) Mole fraction

moles water = 61g / 18.02g/mole  = 3.38513 moles

Total number of moles = moles of ethylene glycol + moles of water = 0.6283 + 3.38513 = 4.0134276 moles

Mole fraction = 0.6283/ 4.0134276 = 0.156549

3 0
3 years ago
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