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3 years ago

5

Is plastic from crude oil biotic or a biotic

1 answer:

Nutka1998 [239]3 years ago

3 0

<span>The truth could prove to be that both mechanisms are correct, or that neither provides a completely accurate picture of how crude oil comes to us. What is certain is that scientists need to avoid letting previous ideas, politics, or even scientific competition prevent them from accepting the truth, whatever that proves to be.</span>

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How to find orbital notation?

AveGali [126]

Orbital notation is a way of writing an electron configuration to provide more specific information about the electrons in an atom of an element.

Orbital notation can be used to determine the quantum numbers of an electron.

6 0

3 years ago

Yuri [45]

the answer is d hope this helps

8 0

3 years ago

Read 2 more answers

Determine the specific heat of a 70 g sample of material that absorbed 96 J as it was heated from 293 K to 313 K

Damm [24]

This problem is providing us with the mass (70 g), absorbed heat (96 J) and initial and final temperatures (293 K and 313 K, respectively) so the specific heat of the material is required and found to be 0.0686 J/(g*K) as shown below:

<h3>Calorimetry:</h3>

In chemistry, we can go over calorimetry by writing the following relationship among heat, mass, specific heat and temperature change:

$Q=mC(T_f-T_i)$

Thus, one can get the specific heat by solving for C in the previous equation:

$C=\frac{Q}{m(T_f-T_i)}$

Hence, we can plug in the given data to obtain:

$C=\frac{96J}{70g(313K-293K)}\\ \\C=0.0686\frac{J}{g*K}$

Learn more about calorimetry: brainly.com/question/1407669

5 0

2 years ago

What is the meaning of polyatomic

Svetllana [295]

Explanation:

consisting of many atoms is known as polyatomic

6 0

4 years ago

A pycnometer is a precisely weighted vessel that is used for highly accurate density determinations. Suppose that a pycnometer h

dexar [7]

Answer:

5.758 is the density of the metal ingot in grams per cubic centimeter.

Explanation:

1) Mass of pycnometer = M = 27.60 g

Mass of pycnometer with water ,m= 45.65 g

Density of water at 20 °C = d = $998.2 kg/m^3$

1 kg = 1000 g

$1 m^3=10^6 cm^3$

$998.2 kg/m^3=\frac{998.2 \times 1000 g}{10^6 cm^3}=0.9982 g/cm^3$

Mass of water ,m'= m - M = 45.65 g - 27.60 g =18.05 g

Volume of pycnometer = Volume of water present in it = V

$Density=\frac{Mass}{Volume}$

$V=\frac{m'}{d}=\frac{18.05 g}{0.9982 g/cm^3}=18.08 cm^3$

2) Mass of metal , water and pycnometer = 56.83 g

Mass of metal,M' = 9.5 g

Mass of water when metal and water are together ,m''= 56.83 g - M'- M

56.83 g - 9.5 g - 27.60 g = 19.7 g

Volume of water when metal and water are together = v

$v=\frac{m''}{d}=\frac{19.7 g}{0.9982 g/cm^3}=19.73 cm^3$

Density of metal = d'

Volume of metal = v' = $\frac{M'}{d'}$

Difference in volume will give volume of metal ingot.

v' = v - V

$v'=19.73 cm^3-18.08 cm^3=$

$v'=1.65 cm^3$

Since volume cannot be in negative .

Density of the metal =d'

= $d'=\frac{M'}{v'}=\frac{9.5 g}{1.65 cm^3}=5.758 g/cm^3$

5 0

3 years ago