Answer:
5.096*10^-8
Explanation:
Given that
The average value of the electromagnetic wave is 310 mW/m²
To find the maximum value of the magnetic field the wave is closest to, we say
Emax = √Erms
Emax = √[(2 * 0.310 * 3*10^8 * 4π*10^-7)]
Emax = √233.7648
Emax = 15.289
Now, with our value of maximum electromagnetic wave gotten, we divide it by speed of light to get our final answer
15.289 / (3*10^8) = 5.096*10^-8 T
Suffice to say, The maximum value of the magnetic field in the wave is closest to 5.096*10^-8
Answer:
Explanation:
a = Δv/Δt = (v₁ - v₀) / (t₁ - t₀)
A a = (10 - 0) / (5 - 0) = 2 m/s²
B a = (10 - 10) / (15 - 5) = 0 m/s²
C a = (5 - 10) / (25 - 15) = - 0.5 m/s²
It will have it’s greatest velocity right before the projectile hits the ground. At the instant it makes contact it become zero and the displacement changes to an upward direction rather than down
Answer:
b)10 m/s^2 up
Explanation:
Immediately after The release from the rocket the acceleration of the instrument package will be same as of the rocket that is 10m/s^2 upward.
This because of newtons law of inertia. The states that a body in state of rest and state of motion will remain in state of rest or motion until and unless any external force is applied on it. Immediately after being released from the rocket inertia will keep the acceleration same. The effect of gravity come gradually.