Answer:
0.014s
Explanation:
Given parameters:
Mass of the ball = 0.058kg
Force = 260N
Velocity of the ball = 63m/s
Unknown:
Time of contact = ?
Solution:
To solve this problem, we apply Newton's second law of motion which is mathematically expressed as;
Ft = m(v - u)
F is the force
t is time
m is the mass
v is the final velocity
u is the initial velocity = 0m/s
Insert the parameters and find t;
260 x t = 0.058(63 - 0)
260t = 3.65
t = 0.014s
Answer:
r=0.127
Explanation:
When connected in series
Current = I
When connected in parallel
Current = 10 I
We know that equivalent resistance
In series R = R₁+R₂
in parallel R= R₁R₂/(R₂+ R₁)
Given that voltage is constant (Vo)
V = I R
Vo = I (R₁+R₂) ------------1
Vo = 10 I (R₁R₂/(R₂+ R₁)) -------2
From above equations
10 I (R₁R₂/(R₂+ R₁)) = I (R₁+R₂)
10 R₁R₂ = (R₁+R₂) (R₂+ R₁)
10 R₁R₂ = 2 R₁R₂ + R₁² + R₂²
8 R₁R₂ = R₁² + R₂²
Given that
r = R₁/R₂
Divides by R₂²
8R₁/R₂ = ( R₁/R₂)²+ 1
8 r = r ² + 1
r ² - 8 r+ 1 =0
r= 0.127 and r= 7.87
But given that R₂>R₁ It means that r<1 only.
So the answer is r=0.127
D loud sound
Hope this helped:)
Aluminum metal is a good example of conductor of electricity while glass and paper are good example of insulators.
<h3>What is a conductor?</h3>
A conductor is material that allows easy passage of electric current through the.
<h3>Examples of conductors</h3>
All metals are good examples conductors. such as aluminum, iron, silver, etc.
<h3>What is a non conductor?</h3>
A non conductor or insulator is a material which does not allow easy passage of electric current through them.
<h3>Examples of insulators</h3>
Thus, aluminum metal is a good example of conductor of electricity while glass and paper are good example of insulators.
The complete question is below:
aluminium,metal,glass,and paper, are examples of what?
Learn more about conductors here: brainly.com/question/24154868
#SPJ1
Answer:
ω = 0.467 rad/s
Explanation:
given,
tangential force exerted by the person = 37.7 N
radius of merry-go-round = 2.75 m
mass of merry-go-round = 144 Kg
angle = 33.2°
moment of inertia
I = 544.5 kg.m²
torque = force x radius
τ = 37.7 x 2.75
τ = 103.675 N.m
angular acceleration


α = 0.190 rad/s²
now
,
distance = 
d = 0.579 rad
we know,
using equation of rotational motion
t = 2.46 s
angular speed
ω = α x t
ω = 0.19 x 2.46
ω = 0.467 rad/s