An 82.0 kg spacewalking astronaut pushes off a 655 kg satellite, exerting a 95.0 N force for the 0.530 s it takes him to straigh
1 answer:
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Answer:
- zero
Explanation:
is the magnetic quantum number.
The only possible value for the magnetic quantum number for an electron in an s orbital is 0.
The first three quantun numbers are:
- n: principal quantum number. It may have positive integer values: 1, 2, 3, 4,5, 6, 7, ...
: Azimuthal or angular momentum quantum number. It may have integer values from 0 to n - 1.
This quantum number is related to the type (or shape) of the orbital:
For s orbitals
For p orbitals
For d orbitals
For f orbitals
In this case, it is an s orbital, so we have .
, the third quantum number can have integer values
to
Since, for the s orbitals , the only possible value for
is zero.
Answer:
F_n = 5.65E-11 N
d = 1.20682E-31 m
Explanation:
F = 3.8E-09 N
where
m = Mass of electron = 9.109E−31 kilograms
G = Gravitational constant = 6.67E-11 m³/kgs²
x = Distance between them
For
Dividing the above equations we get
F_n = 5.65E-11 N
d = 1.20682E-31 m
Answer:
3.38 m/s
Explanation:
Mass of child = m₁ = 25
Initial speed of child = u₁ = 5 m/s
Initial speed of cart = u₂ = 0 m/s
Mass of cart = m₂ = 12 kg
Velocity of cart with child on top = v
This is a case of perfectly inelastic collision
Velocity of cart with child on top is 3.38 m/s