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Anettt [7]
3 years ago
9

An 82.0 kg spacewalking astronaut pushes off a 655 kg satellite, exerting a 95.0 N force for the 0.530 s it takes him to straigh

ten his arms. How far apart are the astronaut and the satellite after 1.0 min.?
Physics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer:

41.41 m

Explanation:

When force F is applied on an object of mass m for time t and velocity v₁ is created

F X t = mv₁

F = 95 N , t = .53 s, m = 655 kg

95 x .53 = 655 x v₁

v₁ = .0768 m/s

Applying conservation of momentum on man and satellite

m₁ v₁ = m₂v₂

655 x .0768 = 82 xv₂

v₂ = .6134 m/s

their relative velocity

= .6134 + .0768

= .6902 ( they are in opposite direction )

After 60 second distance between them

= 60 x .6902 m

= 41.41 m

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An object falling straight down without air resistance is said to be exhibiting
Tanzania [10]

Answer:

Explanation:

If the object is falling straight down it is in free fall.  The difference between that and two-dimensional motion is that 2D motion is parabolic (projectile)

6 0
3 years ago
How do the properties of an electromagnetic wave change as a result of increasing the period of the wave?
astra-53 [7]

Answer:

as the period decreases, the frequency and energy of the wave increase

Explanation:

Electromagnetic waves are oscillations of the electric and magnetic fields, described by maxwell's equations, the speed of the wave is called the speed of light

            c = λ f

            E = E cos (kx - wt)

Angular velocity is related to frequency and period.

           w = 2π f = 2π / T

Let's analyze what happens when the wave period decreases, angular velocity and frequency increase.

This increase in frequency is reflected with the Planck equation in wave energy

                E = h f

Therefore the wave carries more energy and can lead to stronger interactions with matter.

In summary, as the period decreases, the frequency and energy of the wave increase

4 0
3 years ago
The normal is a line perpendicular to the reflecting surface at the point of incidence.
ladessa [460]

Answer:

True

Explanation:

The normal line is defined as the line which is perpendicular to the reflecting surface at the point where the incident ray meet with the reflecting surface.

The angle of incident is defined as the angle which is subtended by the incident ray with respect to the normal ray by consider the normal ray as the base line and angle is measured from the point where incident ray is incident on the reflecting surface of the mirror.

Similarly reflecting ray can be defined as the ray which is reflected after the incident of a ray and the angle subtended by the reflecting ray is measure with respect to normal ray by considering normal ray as a base line.

Therefore, the normal ray is the perpendicular line to the reflecting surface at the point of incidence.

4 0
3 years ago
In the carbon cycle, carbon is found in _______. a. the atmosphere b. the soil c. living organisms d. all of the above
VMariaS [17]

Answer;

All the above

Explanation;

The element carbon is the most important chemical constituent of many organic matter, ranging from fossil fuels to complex molecules  such as DNA and RNA, that control genetic reproduction in organisms.

This element is found stored in major sinks found on the earth;

  • as organic molecules in living and dead organisms found in the biosphere;
  • as the gas carbon dioxide in the atmosphere;
  • as organic matter in soils;
  • in the lithosphere as fossil fuels and sedimentary rock deposits in the oceans as dissolved atmospheric carbon dioxide and
  • as calcium carbonate shells in marine organisms.
7 0
3 years ago
Read 2 more answers
A block with mass m is placed against a spring (with spring constant k) on a frictionless plane inclined with angle θ with respe
dangina [55]

Answer:

b.\Delta U_s

e.\Delta E_{mech}>0

Explanation:

We are given that

Spring constant=k

Angle=\theta

Mass=m

Distance=d

Distance=\Delta x

Initial potential energy of spring=\frac{1}{2}k(\Delta x)^2

Final potential energy of spring=0

Final potential energy  of system=mgd

Initial mechanical energy of system=Initial K.E+Initial P.E=0+0=0

Final mechanical energy of the system=Kinetic energy+Potential energy=0+mgd

\Delta E_{mech}=mgd-0=mgd>0

\Delta U_{s}=Final-initial=0-\frac{1}{2}k(\Delta x)^2=-\frac{1}{2}k(\Delta x)^2=

Option b and e are true.

8 0
3 years ago
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