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Stolb23 [73]
3 years ago
15

A gasoline engine takes in air at 290 K, 90 kPa and then compresses it. The combustion adds 1000 kJ/kg to the air after which th

e temperature is 2050 K.
Using a cold air-standard analysis, i.e., constant specific heats at 300 K, find the compression ratio, compression specific work, and the highest pressure in the cycle. Repeat your analysis assuming temperature-dependent specific heats and comment on your results.

Engineering
1 answer:
Inessa [10]3 years ago
4 0

Answer:

attached below

Explanation:

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An insulated tank having a total volume of 0.6 m3 is divided into two compartments. Initially one compartment contains 0.4 m3 of
IRISSAK [1]

Answer:

a. The final temperature is 69.8°C

b. The final pressure is 2.67bar

c. The amount of entropy produced is 0.38568kJ/K

Explanation:

Pls, check the attached files for detail step by step explanation as typing the solution here can not be explicit.

5 0
3 years ago
A fuel cell vehicle draws 50 kW of power at 70 mph and is 40% efficient at rated power. You are asked to size the fuel cell syst
svetoff [14.1K]

Answer:

  a) fuel cell weight and volume: 50 kg, 33.3 L

  b) fuel tank weight and volume: 321 kg, 643 L

Explanation:

<u>Fuel Cell</u>

Delivery of 50 kW from a source with a power density of 1.5 kW/L requires a source that has a volume of ...

  (50 kW)/(1.5 kW/L) = 33.3 L

The weight of the power source is 1 kW/kg, so will be ...

  (50 kW)/(1 kW/kg) = 50 kg

__

<u>Fuel Tank</u>

400 miles at 70 mph will take (400/70) h ≈ 5.71429 h. In that time, the energy used by the vehicle power plant is ...

  (50 kW)(5.71429 h)(3600 s/h) = 1028.57 MJ

Since the power plant is 40% efficient, it must be supplied with 2.5 times that amount of energy, or 2571.43 MJ.

The tank volume and mass will then be ...

  volume = 2571.43 MJ/(4 MJ/L) = 642.9 L

  mass = 2571.43 MJ/(8 MJ/L) = 321.4 kg

_____

<em>Comment on fuel tank volume</em>

It appears the fuel tank would need to be equivalent in size to a sphere about 1.1 m in diameter.

4 0
3 years ago
Does anyone know what this is​
sammy [17]

Answer:

Looks like mold that got frosted over

Explanation:

4 0
2 years ago
Read 2 more answers
Consider a fan located in a 3 ft by 3 ft square duct. Velocities at various points at the outlet are measured, and the average f
natulia [17]

Answer:

minimum electric power consumption of the fan motor is 0.1437 Btu/s

Explanation:

given data

area = 3 ft by 3 ft

air density = 0.075 lbm/ft³

to find out

minimum electric power consumption of the fan motor

solution

we know that energy balance equation that is express as

E in - E out  = \frac{dE \ system}{dt}    ......................1

and at steady state  \frac{dE \ system}{dt} = 0

so we can say from equation 1

E in = E out

so

minimum power required is

E in = W = m \frac{V^2}{2} = \rho A V \frac{V^2}{2}  

put here value

E in =  \rho A V \frac{V^2}{2}  

E in =  0.075 *3*3* 22 \frac{22^2}{2}  

E in = 0.1437 Btu/s

minimum electric power consumption of the fan motor is 0.1437 Btu/s

5 0
3 years ago
Transcript
posledela

Answer:

O is truse is the best answer hhahahha

Explanation:

8 0
3 years ago
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