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3 years ago

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Which option distinguishes what can be inferred from the following scenario?

1 answer:

dimaraw [331]3 years ago

8 0

Answer:

Option B

Explanation:

A logistician mainly manage the purchasing, transportation, inventory, and warehousing. He/She guide the movement of goods and people from th production plant to the warehouse and then to the consumer. He/She uses software to plan and track the movement of goods/products.

Hence, option B is correct

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A 600-ha farmland receives annual rainfall of 2500 mm. There is a river flowing through the farmland with an inflow rate of 5 m3

shepuryov [24]

Answer:

E = 7333.33 mm

Explanation:

The annual evapotranspiration (E) amount can be calculated using the water budget equation:

$P*A + Q_{in}*\Delta t = E*A + \Delta S + Q_{out}*\Delta t$ (1)

<u>Where</u>:

<em>P: is the precipitation = 2500 mm, </em>

<em>Q(in): is the water flow into the river of the farmland = 5 m³/s, </em>

<em>ΔS: is the change in water storage = 2.5x10⁶ m³, </em>

<em>Q(out): is the water flow out of the river of the farmland = 4 m³/s.</em>

<em>Δt: is the time interval = 1 year = 3.15x10⁷ s </em>

<em>A: is the surface area of the farmland = 6.0x10⁶ m² </em>

Solving equation (1) for ET we have:

$E = \frac{P*A + Q_{in}*\Delta t - \Delta S - Q_{out}*\Delta t}{A}$

$E = \frac{2.5 m \cdot 6.0 \cdot 10^{6} m^{2} + 5 m^{3}/s \cdot 3.15 \cdot 10^{7} s - 2.5 \cdot 10^{6} m^{3} - 4 m^{3}/s \cdot 3.15 \cdot 10^{7} s}{6.0\cdot 10^{6} m^{2}}$

$E = 7333.33 mm$

Therefore, the annual evapotranspiration amount is 7333.33 mm.

I hope it helps you!

3 0

4 years ago

The _____________ is your car’s electrical charger. It’s various parts are contained in an aluminum housing and generate direct

Llana [10]

The Alternator is the only one from this list that I know is a car part so I chose that one

7 0

3 years ago

Legal metrology would protect consumers from businesses that do not take measurements according to defined measuring regulations

sergij07 [2.7K]

From what my research concluded, true

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4 years ago

You want to plate a steel part having a surface area of 160 with a 0.002--thick layer of lead. The atomic mass of lead is 207.19

Pepsi [2]

Answer:

<u><em>To answer this question we assumed that the area units and the thickness units are given in inches.</em></u>

The number of atoms of lead required is 1.73x10²³.

Explanation:

To find the number of atoms of lead we need to find first the volume of the plate:

$V = A*t$

<u>Where</u>:

A: is the surface area = 160

t: is the thickness = 0.002

<u><em>Assuming that the units given above are in inches we proceed to calculate the volume: </em></u>

$V = A*t = 160 in^{2}*0.002 in = 0.32 in^{3}*(\frac{2.54 cm}{1 in})^{3} = 5.24 cm^{3}$

Now, using the density we can find the mass:

$m = d*V = 11.36 g/cm^{3}*5.24 cm^{3} = 59.5 g$

Finally, with the Avogadros number ( $N_{A}$ ) and with the atomic mass (A) we can find the number of atoms (N):

$N = \frac{m*N_{A}}{A} = \frac{59.5 g*6.022 \cdot 10^{23} atoms/mol}{207.19 g/mol} = 1.73 \cdot 10^{23} atoms$

Hence, the number of atoms of lead required is 1.73x10²³.

I hope it helps you!

3 0

3 years ago

A design team is working on creating a new energy-efficient light. They have completed the following steps:

Anastaziya [24]

I believe that it is to produce a product

7 0

3 years ago

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