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k0ka [10]
2 years ago
9

A chemical reaction involves reactant species A, B, and C. Leaving all other factors identical, doubling the concentration of sp

ecies B increases the rate by a factor of 4. The rate of reaction is not affected by changing the concentration of species A. The rate of the reaction is linearly dependent on the concentration of C. What is the rate equation for this reaction?Rate=k[A][B]2[C]Rate=k[A]2[B][C]2Rate=k[A][B][C]Rate=k[B]2[C]Rate=k[B]2[C]2None of the above
Chemistry
1 answer:
umka21 [38]2 years ago
3 0

Answer:

Rate = k . [B]² . [C]

Explanation:

The dependence of the reaction rate on the concentration of the reactants is given by the reaction order of each one, as shown in the rate equation.

Rate=k.[A]^{x} .[B]^{y} .[C]^{z}

where,

k is the rate constant

x, y, z are the reaction orders.

  • <em>The rate of reaction is not affected by changing the concentration of species A.</em> This means that the reaction order for A is x = 0 since when its concentration changes, the rate stays the same.
  • <em>Leaving all other factors identical, doubling the concentration of species B increases the rate by a factor of 4.</em> This means that the reaction order for B is y = 2, so when the concentration is doubled, the new rate is 2² = 4 times the initial rate.
  • The rate of the reaction is linearly dependent on the concentration of C. This means that the reaction order for C is z = 1, that is, a linear dependence.

All in all, the rate equation is:

Rate = k . [B]² . [C]

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What total volume of ozone measured at a pressure of 24.5 mmHg and a temperature of 232 K can be destroyed when all of the chlor
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1.75272\ \text{m}^3

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CF_3Cl + UV \rightarrow CF_3 + Cl

Cl + O_3 \rightarrow ClO + O_2

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ClO + O \rightarrow Cl + O_2

It can be seen that 2 moles of ozone is required in the complete cycle

So for 10 cycles, 20 moles of ozone is required

m = Mass of CF_3Cl = 15.5 g

M = Molar mass of CF_3Cl = 104.46 g/mol

P = Pressure = 24.5 mmHg

T = Temperature = 232 K

R = Gas constant = 62.363\ \text{L mmHg/K mol}

Number of moles is given by

n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{15.5}{104.46}\\\Rightarrow n=0.1484\ \text{moles}

20\ \text{moles} = 20\times 0.1484 = 2.968\ \text{moles}

From ideal gas law we have

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