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2 years ago

Whose main job is to help a plant cell make proteins

Chemistry

2 answers:

Basile [38]2 years ago

8 0

Explanation:

CELL PARTS AND FUNCTIONS

A. B

Ribosomes These small structures function as factories to produce proteins

Golgi Body Receive materials from the. endoplasmic reticulum and send them to other parts of the cell. They also release materials outside the cell

hoa [83]2 years ago

7 0

Answer:

Water

Explanation:

Because water is very important

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Write the following elements in increasing order of atomic radius. Ca, Mg, Be, Sr

Free_Kalibri [48]

Answer:

In increasing order:

Sr, Ca, Mg, Br

6 0

3 years ago

In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for

inessss [21]

Answer:

The standard cell potential of the reaction is 0.78 Volts.

Explanation:

$Cu^{2+}(aq)+Fe(s)\rightarrow Cu(s)+Fe^{2+}(aq)$

Reduction at cathode :

$Cu^+(aq)+2e^-\rightarrow Cu(s)$

Reduction potential of $Cu^{2+}$ to Cu= $E^o_{1}=0.34 V$

Oxidation at anode:

$Fe(s)\rightarrow Fe^{2+}(aq)+2e^-$

Reduction potential of $Fe^{2+}$ to Fe= $E^o_{2}=-0.44 V$

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.34V -(-0.44 V)=0.78 V$

The standard cell potential of the reaction is 0.78 Volts.

3 0

3 years ago

Which of the following is considered a form of technology?

anygoal [31]

Answer:

The answer is B. Hope this helps! please give me brainliest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! =)

8 0

3 years ago

Read 2 more answers

What would be the molarity of a solution in which 0.56 mole of NaCl is dissolved in enough water to make 2.7 L of solution?

yan [13]

Answer:

Molarity = 0.21 M

Explanation:

Moles solute (mol) = Volume solution (L) x Molarity solution (M)

0.56 mol NaCl = 2.7 L x M

M = 0.2074074074

5 0

2 years ago

If 0.255 moles of AgNO₃ react with 0.155 moles of H₂SO₄ according to this UNBALANCED equation below, how many grams of Ag₂SO₄ co

Ber [7]

Answer: 6.162g of Ag2SO4 could be formed

Explanation:

Given;

0.255 moles of AgNO3

0.155 moles of H2SO4

Balanced equation will be given as;

2AgNO3(aq) + H2SO4(aq) -> Ag2SO4(s) + 2HNO3(aq)

Seeing that 2 moles of AgNO3 is required to react with 1 moles of H2SO4 to produce 1 mole of Ag2SO4,

Therefore the number of moles of Ag2SO4 produced is given by,

n(Ag2SO4) = 0.255 mol of AgNO3 ×

[0.155mol H2SO4 ÷ 2 mol AgNO3] x

[ 1 mol Ag2SO4 ÷ 1 mol H2SO4]

= 0.0198 mol of Ag2SO4.

mass = no of moles x molar mass

From literature, molar mass of Ag2SO4 = 311.799g/mol.

Thus,

Mass = 0.0198 x 311.799

= 6.162g

Therefore, 6.162g of Ag2SO4 could be formed

4 0

3 years ago