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elena55 [62]
2 years ago
9

In hydrogen iodide __________________ are the most important intermolecular forces.

Chemistry
1 answer:
lara31 [8.8K]2 years ago
7 0

Answer:

Hydrogen bonding

Explanation:

When Hydrogen interacts with a halogen, it forms hygrogen bonding with that halogen(eg. F, CL, I.... N and O) . Hydrogen bonding is the strongest form of covalent bonding

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1. How many molecules of ammonia can be created when four molecules of nitrogen are combined with four molecules of hydrogen? In
allochka39001 [22]

Explanation:

1. N_2+3H_2\rightarrow 2NH_3

According to reaction , 1 molecule of nitrogen gas reacts with 3 molecules of hydrogen gas to give 2 molecules of ammonia

Then 4 molecules of nitrogen gas will react with:

\frac{3}{1}\times 4 molecules=12 molecules of hydrogen gas.

As we can see that molecules of nitrogen gas are in excess amount.

So, the molecules  of ammonia  formed will depend upon molecules of hydrogen gas.

According to reaction, 3 molecules of hydrogen gas gives 2 molecules of ammonia.

Then 4 molecules of hydrogen gas will give :

= \frac{2}{3}\times 4 molecules=2.667 molecules of ammonia

2) N_2+3H_2\rightarrow 2NH_3

Molecules of nitrogen gas in balanced chemical equation = 1

Molecules of hydrogen gas in balanced chemical equation = 3

The ratio of nitrogen and hydrogen molecules would result in no left-over reactants will be:

\frac{1}{3} = 1 : 3

For every 1 molecule of nitrogen gas molecules 3 molecules of hydrogen gas molecules are required to form.

3) N_2+3H_2\rightarrow 2NH_3

Moles of nitrogen gas = \frac{100.0 g}{28 g/mol}=3.5714 mol

Moles of hydrogen gas = \frac{100.0 g}{2 g/mol}=50.0 mol

According to reaction , 1 mole of nitrogen gas reacts with 3 mole of hydrogen gas to give 2 moles of ammonia

Then 3.5714 moles of nitrogen gas will react with:

\frac{3}{1}\times 3.5714 mol=10.7142 mol of hydrogen gas.

As we can see that moles of nitrogen gas are only reacting with 10.7142 moles of hydrogen gas which means that nitrogen gas is limiting reagent and hydrogen gas is excessive reagent.

So, amount of ammonia gas will depend upon the moles of nitrogen gas.

According to reaction, 1 molecules of nitrogen gas gives 2 molecules of ammonia.

Then 3.5714 mol of nitrogen gas will give :

= \frac{2}{1}\times 3.5714 mol=7.1428 mol of ammonia

Theoretical yield = Mass of 7.1428 moles of ammonia:

7.1428 mol × 17 g/mol = 199.9 g

199.9 g is the theoretical yield of the reaction.

Hydrogen gas  is the excess reactant.

Nitrogen gas is the limiting reactant.

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4 years ago
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